Elevator dynamics — how does the cable tension compare with the weight when a lift (elevator) is moving?

Difficulty: Easy

Correct Answer: it is less when the lift is moving downwards

Explanation:


Introduction / Context:
The apparent tension in an elevator cable depends on the elevator’s acceleration. Understanding this relation helps in sizing hoists and in interpreting load-sensor readings and safety-brake triggers.


Given Data / Assumptions:

  • Elevator car mass m, weight W = mg.
  • Upward acceleration a > 0 when speeding up upward or slowing down downward; downward acceleration a > 0 when speeding up downward or slowing down upward.
  • Neglect cable mass and friction for the basic relation.


Concept / Approach:

Apply Newton’s second law along the vertical. For upward acceleration: T − W = ma ⇒ T = W + ma > W. For downward acceleration: W − T = ma ⇒ T = W − m*a < W. Thus, tension increases above weight when accelerating upward and decreases below weight when accelerating downward.


Step-by-Step Solution:

Identify acceleration direction from motion state (speeding up/down).Write force balance with sign convention upward positive.Solve for T to compare with W for each case.Conclude: tension is less when moving downwards (accelerating downward), and more when moving upwards (accelerating upward).


Verification / Alternative check (if short method exists):

Elevator scale thought experiment: a person’s apparent weight is lower when the car accelerates downward and higher when it accelerates upward, mirroring cable tension behavior.


Why Other Options Are Wrong:

Options claiming constant tension ignore acceleration. Saying “more when moving downwards” reverses the sign. “Less when moving upwards” contradicts Newton’s law for upward acceleration.


Common Pitfalls (misconceptions, mistakes):

Confusing direction of motion with direction of acceleration (e.g., moving up while slowing down implies downward acceleration and reduced tension).


Final Answer:

it is less when the lift is moving downwards

More Questions from Applied Mechanics

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion