A team of $8$ persons joins in a shooting competition. The best marksman scored $85$ points. If he had scored $92$ points, the average score for the team would have been $84$. The number of points, the team scored was
Aptitude
Average
Difficulty: Easy
Choose an option
-
A588
-
B645
-
C665
-
D672
Answer
Correct Answer: 665
Explanation
### Concept & Formula
The total sum of observations is related to the average by the following baseline formula:
$$ \text{Total Score} = \text{Average Score} \times \text{Number of Persons} $$
### Step-by-Step Solution
* **Given:**
* Number of persons in the team = $8$
* Actual score of the best marksman = $85$
* Hypothetical score of the best marksman = $92$
* Hypothetical average score of the team = $84$
* **Calculation:**
Let the actual total score of the team be $T$.
If the marksman scores $92$ instead of $85$, the net increase in the team's total score would be:
$$ 92 - 85 = 7 \text{ points} $$
Therefore, the hypothetical total score becomes $(T + 7)$.
We are given that this hypothetical total score results in an average of $84$ for the $8$ members:
$$ T + 7 = 84 \times 8 $$
$$ T + 7 = 672 $$
$$ T = 672 - 7 = 665 $$
### Exam Strategy & Shortcut
Calculate the hypothetical total directly: $84 \times 8 = 672$.
Since this total is based on an assumed score that is $7$ points higher ($92 - 85 = 7$) than what was actually achieved, simply subtract the difference from the hypothetical total to find the actual score: $672 - 7 = 665$.
### Common Pitfall
A common error is to accidentally add the $7$-point difference to $672$ instead of subtracting it, leading to the incorrect option of $672$ or a completely wrong value. Always remember that the hypothetical condition yields a *higher* total than reality.
### Final Answer
**Therefore, the correct answer is 665.**