Difficulty: Easy
Correct Answer: both chromatids of a chromosome were labeled
Explanation:
Introduction:Classic experiments in chromosome autoradiography provided direct visual evidence for semi-conservative DNA replication. This question revisits the Taylor, Woods, and Hughes study using Vicia faba (broad bean), in which cells incorporated radioactive thymidine during S phase to track newly synthesized DNA strands.
Given Data / Assumptions:
Concept / Approach:When replication is semi-conservative and labeling occurs during the entire S phase, each newly synthesized strand in both sister chromatids will be radioactive. Each chromatid contains one parental unlabeled strand and one labeled nascent strand, so both chromatids show labeling over their lengths in autoradiographs.
Step-by-Step Solution:
Label incorporated during S phase → every new strand synthesized in that cycle is radioactive.Semi-conservative outcome → each sister chromatid receives one new (labeled) strand paired with one old (unlabeled) strand.Therefore, both chromatids of each replicated chromosome appear labeled after that S phase.In a subsequent unlabeled S phase, only one chromatid would remain labeled, matching further semi-conservative expectations.Verification / Alternative check:Meselson–Stahl density-gradient results are consistent with this logic: after one replication, hybrids are formed; autoradiography simply visualizes nascent strand incorporation directly at the chromosomal level.
Why Other Options Are Wrong:
Common Pitfalls:Confusing the pattern after the first labeled S phase with that after a second, unlabeled S phase, when a single chromatid per chromosome retains label.
Final Answer:both chromatids of a chromosome were labeled.
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