Evaporation reduction from reservoirs Which chemical is used to form a monomolecular surface film to minimize evaporation losses from reservoirs?

Difficulty: Easy

Correct Answer: Cetyl alcohol (hexadecanol)

Explanation:


Introduction / Context:
In arid and semi-arid regions, open-water evaporation from reservoirs is a significant loss. One mitigation technique is spreading a monomolecular film of long-chain fatty alcohols on the surface to reduce evaporation by lowering surface tension and suppressing capillary waves.



Given Data / Assumptions:

  • Objective is evaporation reduction, not disinfection or pH modification.
  • Candidates include chemicals with low volatility and ability to spread as a thin film.


Concept / Approach:
Cetyl alcohol (hexadecanol) and stearyl alcohol (octadecanol) are classic film-forming agents used to reduce evaporation. They are hydrophobic, spread spontaneously into a monolayer, and are effective under calm to moderate conditions. Acids, methane, or simple alcohol spirits are unsuitable for sustained monolayer film formation.



Step-by-Step Solution:

Recognize the monomolecular film method for evaporation control.Identify long-chain fatty alcohols as the appropriate chemicals.Select cetyl alcohol (hexadecanol) as the correct choice.


Verification / Alternative check:
Engineering literature documents successful trials using cetyl or stearyl alcohol, sometimes in blends, to reduce evaporation rates.



Why Other Options Are Wrong:
Industrial spirit evaporates quickly and does not form durable films; hydrochloric acid and methane are unsafe/irrelevant; “None of these” is incorrect because an effective agent (cetyl alcohol) exists.



Common Pitfalls:
Confusing “acetyl” with “cetyl”: the effective film former is cetyl alcohol (C16H34O), not acetyl compounds.



Final Answer:
Cetyl alcohol (hexadecanol)

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