Difficulty: Easy
Correct Answer: zero
Explanation:
Introduction / Context:
Superconductors exhibit perfect diamagnetism in the Meissner state, expelling magnetic flux from their interior (except within a thin penetration depth). This behavior can be captured phenomenologically by an effective relative permeability far below unity.
Given Data / Assumptions:
Concept / Approach:
In the Meissner state, internal magnetic flux density B is driven to zero in the bulk. Since B = μ0 μr H for an effective linear description, achieving B ≈ 0 for finite H corresponds to μr ≈ 0. This is a way to express perfect diamagnetism (complete flux expulsion) in a simplified constitutive form.
Step-by-Step Solution:
Recall Meissner effect: superconductors expel magnetic fields.Interpretation: B_inside ≈ 0 except within a thin surface layer.Linearized view: B = μ0 μr H ⇒ μr must be ≈ 0 to cancel B for finite H.Therefore, select μr ≈ 0 (“zero”).
Verification / Alternative check:
London equations predict an exponential decay of magnetic field over the London penetration depth; in the bulk, B approaches zero, consistent with an effective μr near zero.
Why Other Options Are Wrong:
“High” or “either low or high” contradicts perfect diamagnetism; “low” is qualitatively true but not as precise as “zero”.
Common Pitfalls:
Confusing type-II mixed states (flux penetration via vortices) with the ideal Meissner state; overlooking the difference between B and H inside superconductors.
Final Answer:
zero
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