Difficulty: Medium
Correct Answer: 2cos[(C + D)/2]cos[(C - D)/2]
Explanation:
Introduction / Context:
This problem focuses on trigonometric sum to product identities. Converting sums like cos C + cos D into product form is common in trigonometry, signal processing, and exam questions that test formula recall and correct substitution skills.
Given Data / Assumptions:
Concept / Approach:
The standard sum to product identity for cosines is cos C + cos D = 2 cos((C + D)/2) cos((C - D)/2). This identity is distinct from the one for sines and from the difference identity for cosine. The key is to remember which trigonometric function appears in each factor. For cos C + cos D, both factors are cosines, one with half the sum and the other with half the difference of the angles.
Step-by-Step Solution:
Recall the identity: cos C + cos D = 2 cos((C + D)/2) * cos((C - D)/2).Examine each option to see which one matches this structure.Option a is 2cos[(C + D)/2]cos[(C - D)/2], which is exactly the identity we need.Options b and d involve sine functions, which correspond to sum or difference identities for sine rather than cosine.Therefore, the correct product form for cos C + cos D is option a.
Verification / Alternative check:
To verify, choose convenient angles, for example C = 60 degrees and D = 0 degrees. Then cos C + cos D = cos 60 + cos 0 = 0.5 + 1 = 1.5. Now evaluate the right hand side of the identity: 2 cos((C + D)/2) cos((C - D)/2) = 2 cos(30) cos(30). cos 30 is sqrt(3)/2, so the product becomes 2 * (sqrt(3)/2) * (sqrt(3)/2) = 2 * 3/4 = 3/2 = 1.5. The values match, confirming that the identity is correct.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
2cos[(C + D)/2]cos[(C - D)/2]
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