Difficulty: Easy
Correct Answer: 80
Explanation:
Introduction / Context:
This question checks knowledge of basic algebraic identities and how to use them to find expressions like x^2 + y^2 when you know x + y and xy. These types of problems are standard in aptitude tests and help build fluency with algebraic manipulation without solving for x and y individually.
Given Data / Assumptions:
Concept / Approach:
We use the identity (x + y)^2 = x^2 + 2xy + y^2. By rearranging this identity, we can express x^2 + y^2 in terms of (x + y)^2 and xy. This avoids solving for x and y directly. Specifically, x^2 + y^2 = (x + y)^2 - 2xy. Once we substitute the given values of x + y and xy, the computation becomes straightforward.
Step-by-Step Solution:
Start with the identity: (x + y)^2 = x^2 + 2xy + y^2.Rearrange to isolate x^2 + y^2: x^2 + y^2 = (x + y)^2 - 2xy.Substitute x + y = 12 into the formula: (x + y)^2 = 12^2 = 144.Substitute xy = 32: 2xy = 2 * 32 = 64.Therefore, x^2 + y^2 = 144 - 64 = 80.
Verification / Alternative check:
We can verify by finding specific values of x and y that satisfy x + y = 12 and xy = 32. These are roots of the quadratic t^2 - 12t + 32 = 0. Solving gives t = 4 and t = 8, so x and y can be 4 and 8 in either order. Then x^2 + y^2 = 4^2 + 8^2 = 16 + 64 = 80, which matches our result. This confirms that the identity method worked correctly and that the computed value is consistent.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
80
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