More Questions from Statistics

Directions: Study the following pie-chart and bar diagram and answer the following questions Percentage-wise Distribution of students in 6 Different Schools. Total number of students = 6000. Pie chart of percentage-wise Distribution of students in schools Number of Boys in Each School Out of 6000 Students bar chart of distribution of boys What is the sum of the number of girls in School C, the number of girls in School E and the number of boys in School D together ?

Aptitude Statistics Difficulty: Medium
Choose an option
  • A
    1700
  • B
    1900
  • C
    1600
  • D
    1800
  • E
    None of these

Answer

Correct Answer: 1800

Explanation

### Concept & Formula To find the number of girls in a school, we first calculate the total number of students in that school using its percentage share, and then subtract the given number of boys. $$ \text{Number of Girls} = \text{Total Students in School} - \text{Number of Boys} $$ ### Step-by-Step Solution * **Total students in all schools:** 6000 * **Girls in School C:** - Total students in C = $26\%$ of $6000 = 1560$ - Number of boys in C = $900$ - Number of girls in C = $1560 - 900 = 660$ * **Girls in School E:** - Total students in E = $29\%$ of $6000 = 1740$ - Number of boys in E = $1200$ - Number of girls in E = $1740 - 1200 = 540$ * **Boys in School D:** - Given as $600$ * **Required Sum:** - Sum = (Girls in C) + (Girls in E) + (Boys in D) - Sum = $660 + 540 + 600 = 1800$ ### Exam Strategy & Shortcut Instead of calculating $1\%$ of $6000$ every time, remember that $1\%$ is $60$. Total C = $26 \times 60 = 1560$. Total E = $29 \times 60 = 1740$. This drastically speeds up total student calculations for any school. ### Common Pitfall A frequent error is misreading the question and adding the total students of a school rather than specifically filtering out the girls, or accidentally adding girls for School D instead of boys. ### Final Answer Therefore, the correct answer is **1800**.
Discussion & Comments
No comments yet. Be the first to comment!
Join Discussion