The sum of all 2-digit numbers divisible by 5 is
Aptitude
Number System
Difficulty: Medium
Choose an option
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A945
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B1035
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C1230
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D1245
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ENone of these
Answer
Correct Answer: 945
Explanation
### Concept & Formula
A sequence of numbers with a constant difference forms an Arithmetic Progression (A.P.). To find the sum of an A.P., we use the formula:
$$ S = \frac{n}{2}(a + l) $$
Where $n$ is the total number of terms, $a$ is the first term, and $l$ is the last term.
### Step-by-Step Solution
* **Step 1:** Identify the A.P. series.
The 2-digit numbers perfectly divisible by $5$ are: $10, 15, 20, \dots, 95$.
Here, the first term $a = 10$, the last term $l = 95$, and the common difference $d = 5$.
* **Step 2:** Calculate the total number of terms ($n$).
Use the general $n$-th term formula: $l = a + (n-1)d$
$95 = 10 + (n-1)5$
$85 = 5(n-1)$
$17 = n - 1 \Rightarrow n = 18$.
There are $18$ valid terms in total.
* **Step 3:** Calculate the sum of the series.
$S = \frac{18}{2} \times (10 + 95)$
$S = 9 \times 105$
$S = 945$.
### Exam Strategy & Shortcut
**Average Rule:** The sum of any evenly spaced sequence is simply the average of the first and last terms multiplied by the total number of terms.
Average $= \frac{10 + 95}{2} = 52.5$.
The number of terms can be found mentally: $(95 - 10) \div 5 + 1 = 18$.
Sum $= 52.5 \times 18 = 945$. This avoids writing out formal A.P. notation entirely.
### Common Pitfall
The most common mistake is miscounting the number of terms in the set. Many students instinctively divide 100 by 5 to get 20 terms, forgetting that 5 (a 1-digit number) and 100 (a 3-digit number) must be explicitly excluded from the 2-digit constraint requested by the prompt.
### Final Answer
**Therefore, the correct answer is 945.**