In this logical reasoning question on statements and conclusions, you are given three statements about stars, the colour white, and the moon being blue or not. Treat the statements as true even when they differ from real astronomy, read all four conclusions carefully, and then decide which conclusions logically follow. Statements: (I) All stars are white. (II) All white things are moon. (III) No moon is blue. Conclusions: (I) Some moon are stars. (II) No blue is stars. (III) Some white are stars. (IV) Some blue are white.

Introduction / Context:
This problem checks your ability to handle chained categorical statements about stars, white objects, moons, and blue objects. Although the content looks like astronomy, you must ignore actual science and work purely with the logical structure. The three statements define how the sets “stars,” “white,” “moon,” and “blue” relate, and you are asked to judge which conclusions are forced by these relationships.

Given Data / Assumptions:

• Statement (I): All stars are white.
• Statement (II): All white things are moon.
• Statement (III): No moon is blue.
• Conclusion (I): Some moon are stars.
• Conclusion (II): No blue is stars.
• Conclusion (III): Some white are stars.
• Conclusion (IV): Some blue are white.
• Assume that stars exist, so “all stars are white” implies at least some stars and some white objects.

Concept / Approach:
When one statement says “All A are B” and another says “All B are C,” we can chain them to conclude “All A are C.” Likewise, “No C is D” creates a disjoint relationship between sets. Here we chain stars to white and then to moon, and then apply the restriction that moons are never blue. Conclusions are evaluated by checking if they must hold in every Venn diagram that respects all three statements.

Step-by-Step Solution:
Step 1: Draw a large circle for moon.Step 2: Place the white circle completely inside the moon circle because all white things are moon.Step 3: Place the stars circle completely inside the white circle because all stars are white. Therefore, stars are also inside the moon circle.Step 4: Draw a separate region for blue such that it does not intersect the moon circle at all, since no moon is blue.Step 5: Check conclusion (I): “Some moon are stars.” Because the stars circle lies inside the moon circle and we assume there is at least one star, at least one moon is also a star. So conclusion (I) follows.Step 6: Check conclusion (II): “No blue is stars.” All stars lie inside the moon circle, and no moon is blue. Thus stars cannot be blue, so no blue is stars. Conclusion (II) follows.Step 7: Check conclusion (III): “Some white are stars.” Stars lie inside the white circle, and stars exist, so there is at least one object that is both white and star. Therefore conclusion (III) follows.Step 8: Check conclusion (IV): “Some blue are white.” The blue region is completely outside the moon circle, while white lies completely inside moon. So there is absolutely no intersection between blue and white. Conclusion (IV) contradicts the diagram and does not follow.

Verification / Alternative check:
Symbolically, from statement (I), star implies white. From statement (II), white implies moon. Combining, star implies moon. From statement (III), moon implies not blue. Thus star implies not blue. Conclusion (II) matches this reasoning. Since there exists at least one star, there must be at least one white moon that is a star, which supports conclusions (I) and (III). Conclusion (IV) would require some object to be both blue and white, but if white implies moon and moon objects are never blue, such an object cannot exist.

Why Other Options Are Wrong:
Option B claims only conclusions (III) and (IV) follow, but we have already established that (I) and (II) also follow and (IV) is false. Option C includes (IV), which contradicts the condition that moon and blue do not overlap. Option D again includes (IV), so it cannot be correct. Only option A, which includes (I), (II), and (III) while excluding (IV), correctly matches the logical deductions.

Common Pitfalls:
One frequent error is to ignore existence and treat “All stars are white” as not implying any stars, which can cause confusion about conclusions with “some.” In competitive exam conventions, when such chains are used, it is usually intended that there are at least some objects in the mentioned sets. Another mistake is to overlook that white objects are also moon objects, so any restriction on moons automatically restricts white things and thereby restricts stars as well.

Final Answer:
The correct assessment is that only conclusions (I), (II) and (III) follow from the given statements.