Square fencing then inner pavement – Two-step cost:\nFencing a square field at Rs 20 per metre costs Rs 10,080. What will it cost to lay a 3 m wide pavement along the inside edge at Rs 50 per sq m?

Difficulty: Medium

Correct Answer: 73800

Explanation:


Introduction / Context:
First find square side from fencing cost (perimeter known). Inner pavement forms a border strip of uniform width; its area equals area(outer square) − area(inner square).


Given Data / Assumptions:

  • Fencing cost = Rs 10,080 at Rs 20/m ⇒ perimeter P = 10,080 / 20 = 504 m.
  • Square perimeter P = 4s ⇒ side s = 504 / 4 = 126 m.
  • Pavement width w = 3 m; cost rate = Rs 50/sq m.


Concept / Approach:
Area of 3 m wide strip inside = s^2 − (s − 2w)^2 (subtract inner square where each side shrinks by 2w).


Step-by-Step Solution:

Outer area = 126^2 = 15,876 sq m.Inner side = 126 − 2*3 = 120 m ⇒ inner area = 14,400 sq m.Strip area = 15,876 − 14,400 = 1,476 sq m.Cost = 1,476 * 50 = Rs 73,800.


Verification / Alternative check:
Approx strip area ≈ perimeter * width = 504 * 3 = 1,512 m^2 minus corner corrections (~36) ⇒ 1,476 m^2, consistent.


Why Other Options Are Wrong:
43,800 and 53,800 are too low; 83,800 too high; 73,800 matches exact computation.


Common Pitfalls:
Using (s − w)^2 instead of (s − 2w)^2; forgetting to derive s from fencing cost.


Final Answer:
73800

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