Rectangle with given perimeter and difference: The difference between the length and breadth of a rectangle is 23 m, and its perimeter is 206 m. Find the area of the rectangle.

Introduction / Context:
This question checks algebraic handling of perimeter and difference constraints for rectangles, followed by area calculation.

Given Data / Assumptions:

• L - B = 23 m
• Perimeter P = 206 m
• Rectangle perimeter formula: P = 2(L + B)

Concept / Approach:
From P = 2(L + B) we get L + B. With a system L + B and L - B, solve for L and B, then compute area = L * B.

Step-by-Step Solution:

Verification / Alternative check:
Check difference: 63 - 40 = 23. Check perimeter: 2*(63+40) = 2*103 = 206. Consistent.

Why Other Options Are Wrong:
2420, 2320, 2620, 2300 do not match L*B given the exact L and B derived from both equations.

Common Pitfalls:
Using P instead of P/2 for L+B or mixing up which is larger (length vs breadth) leads to wrong numbers.

Final Answer:
2520