Error propagation – Side measured 2% in excess for a square:\nIf the side of a square is measured 2% too high, what is the percentage error in the computed area?

Difficulty: Easy

Correct Answer: 4.04

Explanation:


Introduction / Context:
When a quantity depends on the square of a measurement, a small percentage error in the measurement approximately doubles in the result; exactly, the factor is squared.


Given Data / Assumptions:

  • Side measured = 1.02 * true side.
  • Area ∝ side^2.


Concept / Approach:
Compute exact factor: (1.02)^2 = 1.0404 ⇒ area error = +4.04%.


Step-by-Step Solution:

Let true side = s; measured side = 1.02s.True area = s^2; measured area = (1.02s)^2 = 1.0404 s^2.Percentage error = (1.0404 − 1) × 100% = 4.04%.


Verification / Alternative check:
Approximation 2*(2%) = 4% is close; exact is 4.04%.


Why Other Options Are Wrong:
1.04, 2.04, 3.04 misapply linear approximation or mis-square 1.02.


Common Pitfalls:
Using linear instead of squaring; misinterpreting percentage vs decimal.


Final Answer:
4.04

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