Noncircular ducts: for a square duct of side d, what is the equivalent (hydraulic) diameter to use for heat-transfer calculations?
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Ad
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Bd/2
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C4d/π
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D2d
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Ed/√2
Answer
Correct Answer: d
Explanation
Introduction / Context:Engineering correlations for pressure drop and convection in ducts often employ the hydraulic (equivalent) diameter to account for noncircular cross-sections. For turbulent flow and most design work, the same hydraulic diameter is used for both friction and heat-transfer correlations.
Given Data / Assumptions:
- Square duct with side length d.
- Use of standard equivalent diameter definition Dh = 4A/P, where A is flow area and P is wetted perimeter.
- Application to heat-transfer calculations under typical conditions.
Concept / Approach:Compute Dh using geometry: for a square, A = d^2 and P = 4d. Therefore Dh = 4A/P = 4 d^2 / (4 d) = d. This provides a simple, exact equivalence for the square section. Unless special laminar, developing-flow, or constant-heat-flux corrections are required, Dh = d is used directly in Nusselt, Reynolds, and friction factor correlations.
Step-by-Step Solution:
Write Dh = 4A/P.Insert A = d^2 and P = 4d.Evaluate Dh = 4 d^2 / (4 d) = d.Use Dh = d in heat-transfer correlations.Verification / Alternative check:Handbooks list Dh = characteristic dimension for common shapes; for square ducts Dh equals side length.
Why Other Options Are Wrong:
- d/2 or d/√2: not consistent with 4A/P.
- 4d/π: corresponds to circular equivalence that does not apply here.
- 2d: overestimates the scale and would mispredict Re and Nu.
Common Pitfalls:Mixing hydraulic diameter definitions for laminar fully developed specialized cases; forgetting to use wetted perimeter for partially filled ducts.
Final Answer:d