Difficulty: Easy
Correct Answer: d
Explanation:
Introduction / Context:
Engineering correlations for pressure drop and convection in ducts often employ the hydraulic (equivalent) diameter to account for noncircular cross-sections. For turbulent flow and most design work, the same hydraulic diameter is used for both friction and heat-transfer correlations.
Given Data / Assumptions:
Concept / Approach:
Compute Dh using geometry: for a square, A = d^2 and P = 4d. Therefore Dh = 4A/P = 4 d^2 / (4 d) = d. This provides a simple, exact equivalence for the square section. Unless special laminar, developing-flow, or constant-heat-flux corrections are required, Dh = d is used directly in Nusselt, Reynolds, and friction factor correlations.
Step-by-Step Solution:
Verification / Alternative check:
Handbooks list Dh = characteristic dimension for common shapes; for square ducts Dh equals side length.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing hydraulic diameter definitions for laminar fully developed specialized cases; forgetting to use wetted perimeter for partially filled ducts.
Final Answer:
d
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