Difficulty: Medium
Correct Answer: heated and humidified
Explanation:
Introduction / Context:Air–water contact devices (spray washers, air washers) can heat/cool and humidify/dehumidify air depending on the relative temperatures and vapour pressures. Knowing the direction of heat and mass transfer is crucial for process control.
Given Data / Assumptions:
Concept / Approach:When water is warmer than air, heat flows from water to air, increasing the air's sensible temperature. Simultaneously, provided the water has a higher vapour pressure at its temperature than the partial pressure of vapour in air, evaporation occurs, adding moisture to air (humidification). Thus, the air is heated and humidified.
Step-by-Step Solution:
Compare temperatures: T_water > T_air → heat transfer to air.Vapour pressure at water surface > vapour partial pressure in air → mass transfer of moisture to air.Air outlet condition: higher dry-bulb (heated) and higher humidity ratio (humidified).Verification / Alternative check:Plot the process on a psychrometric chart from the inlet state toward the saturation curve at a higher enthalpy. The trajectory shows both DBT and humidity ratio increasing when water is hotter.
Why Other Options Are Wrong:
Heated and dehumidified: contradicts mass transfer direction; warm water adds, not removes, moisture.Cooled options: violate the given temperature relation (water hotter than air).Unchanged: ignores clear temperature and vapour pressure gradients.
Common Pitfalls:Assuming every air–water contact is adiabatic saturation; the result depends on relative temperatures and flow rates, not a universal rule.
Final Answer:
heated and humidified
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