Sum-of-products (SOP) implementation strategy: Which universal gate family most directly realizes SOP expressions with minimal complication, enabling two-level NAND–NAND realizations and easy inversion where needed?

Difficulty: Easy

Correct Answer: NAND

Explanation:


Introduction / Context:
The sum-of-products (SOP) form is one of the most common ways to describe Boolean functions for hardware realization. Engineers frequently translate an SOP expression into a two-level gate network. Choosing a universal gate family simplifies the build, reduces part types, and eases optimization.



Given Data / Assumptions:

  • SOP means an OR (sum) of multiple AND (product) terms, possibly with complemented literals.
  • We aim for a uniform implementation using a single gate type where possible.
  • De Morgan’s laws permit inversion bubbles to be moved between levels to match available gates.


Concept / Approach:
NAND gates are universal and particularly convenient for SOP. A product term can be created with a NAND followed by inversion; the final sum operation (OR) can be formed by a NAND whose inputs are the NANDed product terms with appropriate bubble placement. This yields a standard two-level NAND–NAND structure equivalent to AND–OR, but built entirely from NANDs.



Step-by-Step Solution:

Start with F = P1 + P2 + ... + Pn, where each Pi is an AND of literals.Realize each Pi using a NAND. The output is the complement of Pi (call it Pi’).Feed all Pi’ signals into a final NAND. By De Morgan, NAND of complements = OR of originals.Thus F is implemented with only NAND gates (two-level NAND–NAND network).


Verification / Alternative check:
Compare to a NOR–NOR approach. NOR is ideal for POS (product-of-sums) implementations. For SOP, NAND–NAND aligns naturally without extra inversion overhead.



Why Other Options Are Wrong:

NOR: Best matches POS, not SOP, for two-level realizations.AND: Not universal alone; needs separate OR and NOT for full functionality.DOOR: Not a logic gate; a distractor.


Common Pitfalls:
Mistaking NOR as equally suitable for SOP; forgetting bubble pushing when converting AND–OR to NAND–NAND; assuming inverters are always needed rather than using intrinsic NAND inversions.


Final Answer:
NAND

More Questions from Combinational Logic Circuits

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion