A single-phase semiconverter supplies a highly inductive R–L load and includes a freewheeling diode across the load. Compare the shapes of output voltage and output current waveforms.
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Aare similar
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Bare not similar
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Cmay be similar or dissimilar
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Dare similar only if firing angle is zero
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Eidentical at any firing angle
Answer
Correct Answer: are not similar
Explanation
Introduction / Context:In semiconverters (half-controlled bridges) feeding highly inductive loads, current tends to be smoothed by inductance while voltage remains pulsed. A freewheeling diode provides a path during source non-conduction, further decoupling current shape from the instantaneous source voltage.
Given Data / Assumptions:
- Highly inductive load ⇒ large L, current ripple small.
- Freewheeling diode (FD) across load.
- Phase-controlled thyristors determine when source applies positive voltage.
Concept / Approach:
Output voltage v_o(t) is a chopped sinusoid (or zero during freewheeling), whereas output current i_o(t) is nearly continuous due to the inductor storing energy and because the FD maintains a current path when the converter is not supplying voltage. Thus v_o(t) and i_o(t) are generally dissimilar in shape.
Step-by-Step Reasoning:
During conduction: v_o(t) ≈ rectified line segment; i_o(t) rises slowly.During freewheeling: v_o(t) ≈ 0 (across load), but i_o(t) continues flowing through FD, decaying slowly.Hence, current is quasi-DC while voltage is pulsed → not similar.Verification / Alternative check:
Waveform sketches from standard texts show pulsed v_o with near-continuous i_o for large L and an FD.
Why Other Options Are Wrong:
- “Are similar/identical”: contradict inductive smoothing and freewheeling action.
- “Only if α = 0”: even at α = 0, v_o is sinusoidal-rectified while i_o is smoothed.
- “May be similar”: not for highly inductive loads with FD.
Common Pitfalls:
- Assuming resistive-load intuition carries over to inductive cases.
- Ignoring FD role in maintaining current when source is off.
Final Answer:
are not similar