Difficulty: Easy
Correct Answer: About 10 times the wavelength of the light carried in the fiber
Explanation:
Introduction / Context:
Single-mode fibers guide only the fundamental mode by using a small core diameter relative to the operating wavelength. Understanding the approximate relationship between core size and wavelength helps explain why single-mode fibers use cores near 8–10 micrometres for common telecom wavelengths around 1.3–1.55 micrometres. This question asks for the appropriate order-of-magnitude multiple.
Given Data / Assumptions:
Concept / Approach:
The V-number (normalized frequency) criterion governs single-mode operation: V = (2 * pi * a / λ) * NA, and single-mode occurs when V < 2.405. For typical refractive index profiles and numerical apertures used in telecom fibers, achieving V near the cutoff yields core radii a that correspond to core diameters on the order of ~8–10 μm at 1.3–1.55 μm wavelengths—roughly 6–10 times the wavelength. Therefore, “about 10 times the wavelength” is a reasonable, rounded statement that matches industry practice.
Step-by-Step Solution:
Verification / Alternative check:
ITU-T G.652 single-mode fibers list mode field diameters near 9–10.5 μm at 1.31 μm and 1.55 μm, reinforcing the “roughly ten times” characterization in common teaching texts.
Why Other Options Are Wrong:
Common Pitfalls:
Treating the multiple as exact rather than an order-of-magnitude rule; confusing core diameter with cladding diameter (usually 125 μm for standard fibers).
Final Answer:
About 10 times the wavelength of the light carried in the fiber.
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