Sine-wave phase reference: At which phase angle does a standard sine wave reach its maximum positive value relative to its zero-phase reference?
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A90°
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B0°
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C−90°
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D360°
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E180°
Answer
Correct Answer: 90°
Explanation
Introduction:Phase angle descriptions help locate key points on a sinusoid. Knowing where maxima and minima occur is essential for phasor analysis, AC power, and signal timing in communication systems.
Given Data / Assumptions:
- Reference sine wave: v(θ) = Vm * sin(θ).
- Phase angle θ measured in degrees from 0° to 360°.
- Conventional positive maximum sought.
Concept / Approach:
The sine function attains its maximum value +1 at θ = 90°. Therefore the waveform’s maximum positive amplitude occurs at 90°. At 270° (or −90°), the sine reaches −1 (negative peak). At 0° and 180°, the waveform crosses zero and reaches zero, respectively, but not the maximum.
Step-by-Step Solution:
Consider v(θ) = Vm * sin(θ).sin(0°) = 0 → zero crossing.sin(90°) = +1 → maximum positive value Vm.sin(270°) = −1 → maximum negative value −Vm.Verification / Alternative check:
Graph of a sine wave or unit-circle evaluation confirms that the peak positive amplitude is at 90°. A derivative check shows dv/dθ = Vm * cos(θ) = 0 at 90°, indicating an extremum; second derivative test confirms it is a maximum.
Why Other Options Are Wrong:
- 0° and 360°: Zero value (start/end of cycle), not maximum.
- −90°: Negative peak, not positive.
- 180°: Another zero crossing with negative slope.
Common Pitfalls:
- Confusing sine with cosine; cosine has its maximum at 0°.
- Mixing degree and radian measures; 90° corresponds to π/2 radians.
Final Answer:
90°