Propagation time of electromagnetic waves: Approximately how long does it take an electromagnetic wave to travel from a transmitter to a receiver 1,000 miles away (assume free-space speed of light)?
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A5.38 ms
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B10.8 ms
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C53.8 ms
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D108 ms
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E0.538 ms
Answer
Correct Answer: 5.38 ms
Explanation
Introduction:Radio and microwave systems rely on finite propagation speed—approximately the speed of light in free space. Estimating one-way delay is vital for ranging, synchronization, and understanding latency in long-distance links.
Given Data / Assumptions:
- Distance D = 1,000 miles (straight-line, free space).
- Propagation speed c ≈ 186,000 miles/s (≈ 3.00 * 10^8 m/s).
- Neglect atmospheric or medium slowdowns.
Concept / Approach:
Travel time t equals distance divided by speed: t = D / c. Using miles keeps arithmetic simple for the given distance. The result is converted to milliseconds for readability.
Step-by-Step Solution:
Write t = D / c.Substitute: t = 1,000 miles / 186,000 miles/s.Compute: t ≈ 0.005376 s.Convert to milliseconds: t ≈ 5.376 ms ≈ 5.38 ms.Verification / Alternative check:
Using SI: 1,000 miles ≈ 1,609 km; c ≈ 300,000 km/s → t ≈ 1,609 / 300,000 s ≈ 0.005363 s (close to the miles-based result). Minor differences stem from rounding c and unit conversions.
Why Other Options Are Wrong:
- 10.8 ms / 53.8 ms / 108 ms: Correspond to longer distances or slower speeds than free-space c.
- 0.538 ms: Ten times too small; would imply ~10,000 miles in 5.38 ms.
Common Pitfalls:
- Confusing one-way delay with round-trip time (RTT); RTT would be roughly twice the one-way value.
- Forgetting that propagation in cables or atmosphere is slightly slower than c, increasing delay.
Final Answer:
5.38 ms