Deflection Comparison – Point Load at Midspan vs Equivalent Uniform Load Two identical simply supported beams have span L and flexural rigidity E I. Beam A carries a point load W at midspan. Beam B carries a uniformly distributed load of intensity w = W / L so that the total load equals W. What is the ratio of maximum deflections delta_A : delta_B?

Difficulty: Medium

Correct Answer: 8 / 5

Explanation:


Introduction / Context:
Serviceability checks often compare deflections under different loading patterns for the same total load. Understanding how load distribution affects deflection is crucial for realistic performance predictions.


Given Data / Assumptions:

  • Simply supported beams, identical L and E I.
  • Beam A: central point load W.
  • Beam B: uniform load with total W, so w = W / L.
  • Linear elastic, small deflection, prismatic sections.


Concept / Approach:

Use standard closed-form deflection formulas and take the ratio. The maximum deflection occurs at midspan for both cases under the given loads.


Step-by-Step Solution:

Beam A: delta_A = W L^3 / (48 E I)Beam B: delta_B = 5 w L^4 / (384 E I) with w = W / LSubstitute: delta_B = 5 (W / L) L^4 / (384 E I) = 5 W L^3 / (384 E I)Form ratio: (delta_A) / (delta_B) = (W L^3 / 48) / (5 W L^3 / 384) = 384 / 240 = 8 / 5


Verification / Alternative check:

Energy methods or numerical integration give the same ratio because both deflections scale with W L^3 / (E I), and only coefficients differ.


Why Other Options Are Wrong:

5 / 8 is the reciprocal. 4 / 5 and 3 / 2 are not obtained from standard coefficients. 2 ignores the correct constants in the solution.


Common Pitfalls:

Confusing total load with intensity, applying W as w directly, or forgetting that the UDL deflection coefficient is 5/384.


Final Answer:

8 / 5

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion