Developmental genetics — Drosophila sex determination: When is the Sex-lethal (sxl) gene transcribed with respect to the X:autosome (X:A) balance?

Difficulty: Medium

Correct Answer: When the X:A ratio is 1.0 or greater

Explanation:


Introduction / Context:
In Drosophila melanogaster, primary sex determination depends on the X chromosome to autosome ratio (X:A). The master regulator Sex-lethal (sxl) initiates the female-specific splicing cascade when the X:A balance indicates a female genotype.



Given Data / Assumptions:

  • X:A = 1.0 (e.g., XX with two autosome sets) corresponds to female.
  • X:A = 0.5 (e.g., XY with two autosome sets) corresponds to male.
  • sxl early promoter activity reflects numerator/denominator gene balance.


Concept / Approach:
In embryos with X:A ≥ 1.0, transcription from the early sxl promoter is initiated, leading to production of Sxl protein that enforces female-specific splicing of transformer (tra) and doublesex (dsx) transcripts. In embryos with X:A = 0.5, sxl is not activated, and male development proceeds.



Step-by-Step Solution:

Relate genotype to ratio: XX:AA → 1.0; XY:AA → 0.5.Recall regulatory logic: sxl ON in females (ratio ≥ 1), OFF in males (ratio 0.5).Select the option matching sxl transcription conditions.Conclude: sxl is transcribed when X:A is 1.0 or greater.


Verification / Alternative check:
Genetic mosaics and mutations in numerator (X-linked) and denominator (autosomal) elements shift sxl activation in predictable ways, validating the ratio mechanism.



Why Other Options Are Wrong:

  • X:A < 0.5 or = 0.5 correspond to male pathway; sxl remains OFF.
  • “None” is incorrect because a definitive rule exists.


Common Pitfalls:
Confusing Drosophila ratio-based sex determination with mammalian SRY-based determination; mechanisms differ fundamentally.



Final Answer:
When the X:A ratio is 1.0 or greater

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