Series current continuity — in an ideal series circuit at steady state, the current leaving a resistor is equal to the current entering that resistor. Evaluate this statement.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Current continuity is a direct consequence of charge conservation. In a series circuit, every element experiences the same current because there is only one path for charges to move. Recognizing this allows you to simplify analysis and avoid mistakes such as summing currents in series networks (which is unnecessary and incorrect).


Given Data / Assumptions:

  • Ideal conductors and resistors.
  • Steady-state DC (though the principle applies to AC instantaneously as well).
  • No parallel leakage paths or measurement shunts.


Concept / Approach:
Kirchhoff’s Current Law (KCL) states that the algebraic sum of currents at a node is zero. In series, a node exists between elements but does not branch; thus, current entering that node must equal current leaving it. Consequently, current in any series element is identical to current in every other series element.


Step-by-Step Solution:

Select any resistor in a series chain.Label the entering current as I_in and the leaving current as I_out.Apply KCL to the node on either side of the resistor: ΣI = 0 implies I_in = I_out.Conclude that the statement is correct for ideal series circuits.


Verification / Alternative check:
Measure with an ammeter placed in different series positions; readings are the same. Simulations (SPICE) confirm identical branch currents when no parallel branches exist.


Why Other Options Are Wrong:

“Incorrect” and the conditional options contradict KCL and the nature of a single, unbranched path.


Common Pitfalls:
Confusing series with parallel (in parallel, currents differ by branch conductance); overlooking small unintended branches like meter shunts that slightly alter currents.


Final Answer:
Correct

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