Total current in a series circuit — should you add individual branch currents to obtain the total current in a single-path series network?

Difficulty: Easy

Correct Answer: Incorrect — the same current flows through every series element

Explanation:


Introduction / Context:
Students often confuse rules for series and parallel networks. In a single-path series circuit, current does not split; thus, “adding currents” has no meaning because there is only one current everywhere in the loop. Recognizing this prevents calculation errors and misinterpretation of ammeter readings.


Given Data / Assumptions:

  • A single closed series path (no branches).
  • Ideal components and wiring.
  • Steady-state operation.


Concept / Approach:
By definition, series elements carry identical current. KCL at each internal node implies current entering equals current leaving; with no branching nodes, the same current traverses all components. Therefore, the total current drawn from the source is simply that one current value, obtained via I = V_source / R_total for resistive networks, not a sum of separate branch currents (as would be the case for parallel networks).


Step-by-Step Solution:

Compute equivalent resistance: R_total = ΣRi for series resistors.Apply Ohm’s law: I = V_source / R_total.Recognize that this I is the same through each resistor: I1 = I2 = … = I.Conclude there is no summation of currents in series; there is only one current.


Verification / Alternative check:
Insert an ammeter at different series points; readings are identical, confirming that current is not distributed among branches but remains singular in magnitude and direction (for DC).


Why Other Options Are Wrong:

“Add the currents”: applies to parallel branches, not to a single series path.Frequency, value equality, or capacitors do not change the series current principle for the same instantaneous current in each element.


Common Pitfalls:
Confusing series and parallel behaviors; overlooking small leakage or measurement branches that can create unintended parallel paths.


Final Answer:
Incorrect — the same current flows through every series element

More Questions from Series Circuits

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion