Section modulus of a rectangular section – proportional dependence For a rectangular cross-section of width b and overall depth d, the elastic section modulus Z about the centroidal horizontal axis is proportional to which of the following?

Difficulty: Easy

Correct Answer: Product of the area and the depth (b d × d)

Explanation:


Introduction / Context:
The elastic section modulus Z connects bending moment to extreme fibre stress via sigma_max = M / Z. For rectangular sections used in beams, knowing how Z scales helps with rapid sizing.



Given Data / Assumptions:

  • Rectangular section with width b and depth d.
  • Bending about the centroidal horizontal axis (through mid-depth).
  • Linear elastic behavior.



Concept / Approach:
Moment of inertia about the centroidal horizontal axis is I = b d^3 / 12. Distance to the extreme fibre is y_max = d / 2. Hence section modulus Z = I / y_max = (b d^3 / 12) / (d/2) = b d^2 / 6. Since area A = b d, it follows Z ∝ A * d.



Step-by-Step Solution:
I = b d^3 / 12.y_max = d / 2.Z = I / y_max = (b d^3 / 12) / (d/2) = b d^2 / 6.Express in terms of area: A = b d → Z = (A d) / 6 → proportional to A * d.



Verification / Alternative check:
Dimensional check: Z has units of length^3; A * d has units of length^3, confirming consistency.



Why Other Options Are Wrong:
Area only or area squared give incorrect scaling. Area × width becomes A * b = b^2 d, not proportional to b d^2. Half of I is not Z; Z depends on I divided by y_max.



Common Pitfalls:
Using I directly instead of Z; forgetting to divide by the extreme fibre distance.



Final Answer:
Product of the area and the depth (b d × d)

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