A train covers a certain distance in 50 minutes at an average speed of 48 km/h. To reduce the total journey time to 40 minutes for the same distance, at what constant speed must the train run?

Difficulty: Easy

Correct Answer: 60 km/h

Explanation:

Introduction / Context:Speed, distance, and time are related by distance = speed * time. For a fixed distance, if time decreases, speed must increase proportionally to keep distance constant.

Given Data / Assumptions:

  • Initial speed v1 = 48 km/h; time t1 = 50 minutes = 5/6 h.
  • Target time t2 = 40 minutes = 2/3 h.
  • Distance remains the same.

Concept / Approach:Compute the distance from the first leg, then divide by the new time to get the required speed.

Step-by-Step Solution:

Distance D = 48 * (5/6) = 40 kmRequired speed v2 = D / (2/3) = 40 / (2/3) = 60 km/h

Verification / Alternative check:Proportion method: v2 / v1 = t1 / t2 = (50) / (40) = 1.25, hence v2 = 48 * 1.25 = 60 km/h.

Why Other Options Are Wrong:All other speeds fail to achieve 40 km in 40 minutes.

Common Pitfalls:Not converting minutes to hours; mixing up proportionality (speed inversely proportional to time for fixed distance).

Final Answer:60 km/h

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