Difficulty: Medium
Correct Answer: 12
Explanation:
Introduction / Context:
This question is a standard coins and ratio problem from quantitative aptitude. It tests your ability to translate a ratio into actual numbers, handle mixed denominations, and set up an equation using the total monetary value. Such questions appear frequently in banking, clerical, and management entrance tests.
Given Data / Assumptions:
Concept / Approach:
Main ideas:
Step-by-Step Solution:
Let the numbers of coins be: ₹1 coins = 6k, 50 paise coins = 3k, 10 paise coins = 2k.
Values in rupees: ₹1 coin is 1, 50 paise is 0.5, and 10 paise is 0.1.
Total value V = 6k * 1 + 3k * 0.5 + 2k * 0.1.
Compute: V = 6k + 1.5k + 0.2k = 7.7k.
Given total value is ₹30.80, so 7.7k = 30.80.
Solve for k: k = 30.80 / 7.7 = 4.
Number of 50 paise coins = 3k = 3 * 4 = 12.
Verification / Alternative check:
Check the total value using k = 4. Numbers of coins: ₹1 coins = 24, 50 paise = 12, 10 paise = 8. Total value = 24 * 1 + 12 * 0.5 + 8 * 0.1 = 24 + 6 + 0.8 = 30.8, that is ₹30.80. This matches the given total, confirming our solution.
Why Other Options Are Wrong:
Option a: 8 would make the total value smaller, and the equation 7.7k = 30.80 would not hold.
Option b: 24 would correspond to k = 8, giving a total much larger than ₹30.80.
Option d: 4 makes k = 4/3, which does not satisfy the original total value condition.
Option e: 16 would give k = 16/3, again not consistent with the total sum.
Common Pitfalls:
Common mistakes include forgetting to convert paise to rupees, treating the ratio numbers as actual counts without using a common factor, and miscalculating the total value. Always maintain consistent units (rupees here) and carefully multiply each coin type by its value and its count before forming the equation.
Final Answer:
The bag contains 12 coins of 50 paise.
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