Difficulty: Easy
Correct Answer: 16x^2 - 56x + 49
Explanation:
Introduction / Context:
This question is about expanding the square of a binomial, a very common algebra skill. Recognising and applying the identity for (a − b)^2 or (a + b)^2 allows you to quickly convert a compact expression into a standard polynomial form, which is heavily used in solving quadratic equations and simplifying algebraic expressions.
Given Data / Assumptions:
Concept / Approach:
Main identity:
Step-by-Step Solution:
Write the binomial square: (7 − 4x)^2.
Identify a = 7 and b = 4x.
Compute a^2 = 7^2 = 49.
Compute 2ab = 2 * 7 * 4x = 56x.
Compute b^2 = (4x)^2 = 16x^2.
Apply the identity: (7 − 4x)^2 = a^2 − 2ab + b^2.
So (7 − 4x)^2 = 49 − 56x + 16x^2.
Rearrange into standard quadratic order: 16x^2 − 56x + 49.
Verification / Alternative check:
You can expand directly by multiplication: (7 − 4x)(7 − 4x). Multiply term by term: 7 * 7 = 49, 7 * (−4x) = −28x, (−4x) * 7 = −28x, and (−4x) * (−4x) = 16x^2. Adding these gives 49 − 56x + 16x^2, which matches the result from the identity.
Why Other Options Are Wrong:
Option a: 16x^2 − 28x + 49 uses 28x instead of 56x, forgetting that the middle term is twice the product ab.
Option b and option c: These forms either have incorrect coefficients or wrong signs for the quadratic term and do not match the proper expansion.
Option e: 49 + 56x + 16x^2 corresponds to (7 + 4x)^2, not (7 − 4x)^2, so the middle term has the wrong sign.
Common Pitfalls:
A frequent error is to forget the factor of 2 in the middle term or to mis-handle the sign when the binomial includes a minus. Carefully applying the identity and double checking the sign of 2ab prevents such mistakes.
Final Answer:
The expanded quadratic expression is 16x^2 − 56x + 49.
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