Difficulty: Easy
Correct Answer: Sigma subunit
Explanation:
Introduction / Context:
Bacterial RNA polymerase core enzyme requires an additional specificity factor to recognize promoter sequences efficiently. This highlights how transcription initiation is regulated at the level of polymerase–DNA recognition.
Given Data / Assumptions:
Concept / Approach:
The sigma (σ) factor binds core polymerase to form the holoenzyme, enabling recognition of −35/−10 elements. Different σ factors direct transcription of distinct regulons (e.g., heat shock, sporulation).
Step-by-Step Solution:
Identify removable specificity factor → σ.
Confirm role: promoter recognition and closed-complex formation.
Choose “Sigma subunit”.
Verification / Alternative check:
In vitro, core polymerase binds DNA weakly and initiates poorly; adding σ restores accurate start site selection.
Why Other Options Are Wrong:
α participates in assembly and regulation; β and β' form catalytic center; ω assists assembly/stability; δ is not a standard E. coli subunit.
Common Pitfalls:
Thinking α or β control specificity; confusing σ with transcription factors that bind DNA directly.
Final Answer:
Sigma subunit.
Discussion & Comments