Difficulty: Easy
Correct Answer: Sigma subunit
Explanation:
Introduction / Context: Bacterial RNA polymerase core enzyme requires an additional specificity factor to recognize promoter sequences efficiently. This highlights how transcription initiation is regulated at the level of polymerase–DNA recognition.
Given Data / Assumptions:
Concept / Approach: The sigma (σ) factor binds core polymerase to form the holoenzyme, enabling recognition of −35/−10 elements. Different σ factors direct transcription of distinct regulons (e.g., heat shock, sporulation).
Step-by-Step Solution: Identify removable specificity factor → σ. Confirm role: promoter recognition and closed-complex formation. Choose “Sigma subunit”.
Verification / Alternative check: In vitro, core polymerase binds DNA weakly and initiates poorly; adding σ restores accurate start site selection.
Why Other Options Are Wrong: α participates in assembly and regulation; β and β' form catalytic center; ω assists assembly/stability; δ is not a standard E. coli subunit.
Common Pitfalls: Thinking α or β control specificity; confusing σ with transcription factors that bind DNA directly.
Final Answer: Sigma subunit.
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