Reversed alphabet indexing – If the English alphabet is written in reverse order (Z to A left-to-right), which letter is 7th to the left of the 11th letter from the right end?

Introduction / Context:
This problem uses the same reversed-alphabet setup. We first identify the 11th letter from the right, then move 7 places to the left. Left and right must be interpreted with respect to the reversed sequence written left-to-right as Z, Y, X, …, A.

Given Data / Assumptions:

• Reversed indices: 1:Z, 2:Y, 3:X, 4:W, 5:V, 6:U, 7:T, 8:S, 9:R, 10:Q, 11:P, 12:O, 13:N, 14:M, 15:L, 16:K, 17:J, 18:I, 19:H, 20:G, 21:F, 22:E, 23:D, 24:C, 25:B, 26:A.
• 11th from the right corresponds to reversed index 26 − (11 − 1) = 16.
• Then move 7 steps to the left → subtract 7 from the reversed index.

Concept / Approach:
Compute index of the 11th from right: 16, which is K. Now move 7 to the left: 16 − 7 = 9. The letter with reversed index 9 is R. Index arithmetic is the cleanest approach to avoid double reversals in your head.

Step-by-Step Solution:
Find reference: 11th from right → reversed index 16 → K.Shift left 7: 16 − 7 = 9 → letter R.Hence the answer is R.

Verification / Alternative check:
Convert via normal positions: K has normal position 11, so rpos(K) = 27 − 11 = 16. After a left shift of 7, rpos = 9; convert back: pos = 27 − 9 = 18, which is R (A=1 → R=18). Both methods align.

Why Other Options Are Wrong:

• W/H/D/G correspond to different reversed indices and do not arise from the required two-step navigation.

Common Pitfalls:
Forgetting to convert “from the right” to a reversed index, or accidentally adding instead of subtracting when moving to the left. Keep a small index table handy for sanity checks.

Final Answer:
R