Resistor color code validation (5-band): A 2% 55 kΩ fixed resistor would be coded as green, green, black, red, red. Evaluate this statement for correctness.
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ACorrect
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BIncorrect
Answer
Correct Answer: Correct
Explanation
Introduction / Context:Five-band resistor color codes use the first three bands for significant digits, the fourth for the multiplier, and the fifth for tolerance. Verifying codes quickly is essential in troubleshooting and assembly.
Given Data / Assumptions:
- Nominal value: 55 kΩ = 55,000 Ω.
- Tolerance: 2% (typically red).
- Five-band scheme: digit-digit-digit, multiplier, tolerance.
Concept / Approach:Translate the proposed bands into numbers. Green = 5, black = 0, red multiplier = 10^2, red tolerance = 2%. The first three bands must represent 550 (5, 5, 0). With multiplier 10^2, the value is 550 * 100 = 55,000 Ω = 55 kΩ.
Step-by-Step Solution:
Band 1: green → 5.Band 2: green → 5.Band 3: black → 0 (three-digit format → 550).Band 4: red multiplier → 10^2 = 100.Band 5: red tolerance → 2%.Verification / Alternative check:Compute nominal: 550 * 100 = 55,000 Ω. Compare to target: 55 kΩ. Tolerance color matches 2%, confirming correctness.
Why Other Options Are Wrong:Incorrect: Conflicts with the direct calculation from standardized color assignments.
Common Pitfalls:Confusing 4-band with 5-band rules, misplacing the third digit, or misreading red as 10^3 (which is orange). Also, reading the resistor in reverse can swap tolerance and first digit.
Final Answer:Correct