Waveforms and time–frequency relationship: which statement best describes how the period of a waveform relates to its frequency in basic AC circuit theory?

Difficulty: Easy

Correct Answer: A longer period corresponds to a lower frequency

Explanation:


Introduction / Context:
In alternating-current (AC) theory and signal analysis, time-domain and frequency-domain descriptions are linked by a simple inverse relationship. Recognizing how period and frequency relate is foundational for analyzing power systems, audio signals, and communication waveforms.


Given Data / Assumptions:

  • Frequency f is measured in hertz (cycles per second).
  • Period T is measured in seconds per cycle.
  • Sine wave behavior is representative for illustrating the f–T relationship.


Concept / Approach:
The fundamental relationship is f = 1 / T. As the time for one cycle (T) increases, the number of cycles per second (f) decreases proportionally, and vice versa. Amplitude is independent of frequency; and 1.41 (square root of 2) relates RMS and peak of a sine wave’s amplitude, not its frequency. There is no default “assumed” frequency unless specified by a standard within a given context (e.g., regional mains frequency).


Step-by-Step Solution:

Start with identity: f = 1 / T. Infer monotonic relation: if T goes up, f goes down. Conclude: the correct qualitative statement is “longer period → lower frequency.”


Verification / Alternative check:
Example: if T = 0.02 s, f = 1 / 0.02 = 50 Hz; if T doubles to 0.04 s, f halves to 25 Hz. This numerical check confirms the inverse relation.


Why Other Options Are Wrong:

1.41 factor concerns amplitude (peak vs. RMS), not frequency. Assumed 60 Hz is context-dependent; not a universal default. Amplitude does not set frequency; they are independent attributes. None: incorrect because the period–frequency inverse is correctly stated in option D.


Common Pitfalls:
Confusing amplitude–RMS relationships with frequency, or assuming regional mains frequency applies universally. Always rely on f = 1 / T to reason about time and frequency.


Final Answer:
A longer period corresponds to a lower frequency

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