Difficulty: Easy
Correct Answer: A longer period corresponds to a lower frequency
Explanation:
Introduction / Context:
In alternating-current (AC) theory and signal analysis, time-domain and frequency-domain descriptions are linked by a simple inverse relationship. Recognizing how period and frequency relate is foundational for analyzing power systems, audio signals, and communication waveforms.
Given Data / Assumptions:
Concept / Approach:
The fundamental relationship is f = 1 / T. As the time for one cycle (T) increases, the number of cycles per second (f) decreases proportionally, and vice versa. Amplitude is independent of frequency; and 1.41 (square root of 2) relates RMS and peak of a sine wave’s amplitude, not its frequency. There is no default “assumed” frequency unless specified by a standard within a given context (e.g., regional mains frequency).
Step-by-Step Solution:
Verification / Alternative check:
Example: if T = 0.02 s, f = 1 / 0.02 = 50 Hz; if T doubles to 0.04 s, f halves to 25 Hz. This numerical check confirms the inverse relation.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing amplitude–RMS relationships with frequency, or assuming regional mains frequency applies universally. Always rely on f = 1 / T to reason about time and frequency.
Final Answer:
A longer period corresponds to a lower frequency
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