Capacitor design fundamentals: which single design change will increase the capacitance value of a parallel-plate capacitor, all else being equal?

Difficulty: Easy

Correct Answer: Increasing the area of the plates

Explanation:


Introduction / Context:
Capacitance measures a component’s ability to store electric charge per unit voltage. For the widely taught parallel-plate model, geometric and material parameters determine the capacitance. Knowing which adjustments raise the capacitance is crucial for design, tuning, and selection of capacitors in circuits.


Given Data / Assumptions:

  • Parallel-plate capacitor approximation applies.
  • Plate separation and dielectric permittivity remain unchanged unless stated.
  • We compare the effect of changing a single parameter.


Concept / Approach:
The ideal formula for a parallel-plate capacitor is C = epsilon * A / d, where epsilon is the absolute permittivity (epsilon = epsilon_r * epsilon_0), A is plate area, and d is plate separation. From this, increasing A increases C linearly, decreasing d increases C, and using a higher-permittivity dielectric increases C. Changing frequency or applied voltage does not change the intrinsic capacitance of a linear capacitor; those affect reactance Xc = 1 / (2 * pi * f * C) and stored energy E = 0.5 * C * V^2, respectively, but not C itself.


Step-by-Step Solution:

Recall C = epsilon * A / d for a parallel-plate capacitor. Hold epsilon and d constant as implied, vary A. Increasing A → proportionally larger C.


Verification / Alternative check:
Doubling plate area doubles capacitance in the ideal model. Practical capacitors use stacked or rolled plates to maximize effective area for higher C values, confirming the principle in real-world designs.


Why Other Options Are Wrong:

Decreasing area reduces C. Increasing frequency changes reactance, not C. Increasing voltage changes stored energy, not C for linear dielectrics. None: invalid because increasing area does increase C.


Common Pitfalls:
Confusing frequency-dependent reactance with capacitance, and assuming voltage level alters C. Only geometry and dielectric properties set C for linear capacitors.


Final Answer:
Increasing the area of the plates

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