Difficulty: Easy
Correct Answer: Trouton's rule
Explanation:
Introduction / Context:
Trouton’s rule states that the entropy of vaporization at the normal boiling point of many non-associating liquids is approximately constant, about 85–88 J/mol·K. This empirical regularity provides a simple link between latent heat and boiling point via ΔHvap ≈ Tb * ΔSvap.
Given Data / Assumptions:
Concept / Approach:
Because ΔSvap at Tb is roughly constant for many liquids, ΔHvap scales approximately with Tb. Antoine equation correlates vapour pressure vs temperature, not directly ΔHvap; Kopp’s rule estimates heat capacity from atomic contributions; Kistyakowsky is not the relevant common name here. Thus, the correct named relation is Trouton’s rule.
Step-by-Step Solution:
Recall ΔSvap ≈ constant at Tb.Therefore, ΔHvap ≈ Tb * constant.Select Trouton’s rule.
Verification / Alternative check:
Comparing liquids like benzene, toluene, hexane shows ΔHvap/Tb values clustering around Trouton’s constant, except for hydrogen-bonded liquids like water.
Why Other Options Are Wrong:
Antoine is Pvap–T; Kopp is for heat capacity; “Clapeyron integral” is a general thermodynamic relation, not the empirical rule asked.
Common Pitfalls:
Applying Trouton’s rule to strongly associating liquids leads to significant errors.
Final Answer:
Trouton's rule
Discussion & Comments