Difficulty: Easy
Correct Answer: temperature
Explanation:
Introduction / Context:
The heat (enthalpy) of reaction reflects the enthalpy difference between products and reactants at a specified temperature and pressure. Kirchhoff’s law shows how the standard reaction enthalpy changes with temperature via the difference in heat capacities of products and reactants.
Given Data / Assumptions:
Concept / Approach:
For ideal gases and most condensed phases, enthalpy is primarily a function of temperature. Pressure effects on enthalpy are small (zero for ideal gases). Therefore, the heat of reaction at standard pressure varies with T according to ΔH°(T2) = ΔH°(T1) + ∫(ΔCp) dT. Pressure may affect equilibrium and volume work but not the enthalpy change itself in the ideal approximation.
Step-by-Step Solution:
State ΔH depends on temperature through heat capacities.For ideal gases, ∂H/∂p = 0, so pressure has no direct effect.Therefore select “temperature.”
Verification / Alternative check:
Thermodynamic identities confirm enthalpy’s T dependence; Joule–Thomson effects are separate phenomena and small under standard conditions.
Why Other Options Are Wrong:
Pressure alone does not change ΔH° materially for ideal gases/condensed phases; “both” overstates; “neither” understates; “composition only” ignores the clear T dependence.
Common Pitfalls:
Confusing equilibrium position (pressure dependent) with reaction enthalpy (temperature dependent).
Final Answer:
temperature
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