Relation between air base and photographic base: for successive vertical photographs with flying height H and focal length f, how are the ground air base B and the image photographic base b related?
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AB = (H / f) * b
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BB = (f / H) * b
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Cb = (H / f) * B
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DB = (H * f) / b
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Eb = (f / H) * B
Answer
Correct Answer: B = (H / f) * b
Explanation
Introduction / Context:In aerial photogrammetry, the air base B is the ground distance between successive exposure stations, while the photographic base b is the distance between corresponding principal points on the overlapping photographs. Their relation under vertical photography links image geometry to ground geometry.
Given Data / Assumptions:
- Vertical photographs with negligible tilt.
- Flying height above datum = H; camera focal length = f.
- Scale approximately uniform: scale ≈ f / H at the principal point.
Concept / Approach:Linear distances on the photo are related to ground distances by the scale factor f / H. Thus, a ground distance equals the corresponding photo distance multiplied by H / f. Applying this to the inter-exposure distance yields B = (H / f) * b.
Step-by-Step Solution:Scale at principal point: photo length / ground length = f / H.Rearrange: ground length = (H / f) * photo length.Let photo length = b → ground length (air base) B = (H / f) * b.
Verification / Alternative check:Dimensional reasonableness: larger H increases B for a fixed b, matching intuition; larger f reduces scale and thus reduces computed B for fixed b.
Why Other Options Are Wrong:
- B = (f / H) * b or b = (H / f) * B invert the scale mapping.
- B = (H * f) / b is dimensionally inconsistent.
- b = (f / H) * B restates the inverse but fails to answer the form asked.
Common Pitfalls:Confusing scale f/H with its reciprocal H/f; ignoring minor variations in scale away from the principal point.
Final Answer:B = (H / f) * b