Reinforced concrete beam safety check: A beam of width 25 cm with an effective lever arm (jd) of 40 cm resists a shear force of 6 t; the permissible (safe) shear stress is 5 kg/cm² and the applied bending moment is 24 t·m. Assess the beam's adequacy in shear under these conditions.
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Ais safe in shear
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Bis unsafe in shear
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Cis over safe in shear
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Dneeds redesigning
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Esafe in bending but unsafe in shear
Answer
Correct Answer: is unsafe in shear
Explanation
Introduction / Context:
This problem tests the fundamental shear capacity check for a reinforced concrete (R.C.C.) beam using working-stress style calculations. Even if a beam satisfies bending, it must also be verified that the nominal shear stress does not exceed the permissible (safe) shear stress for the concrete section.
Given Data / Assumptions:
- Beam breadth (b) = 25 cm.
- Effective lever arm (jd) ≈ 40 cm (used as the effective depth for shear check in this classic formulation).
- Shear force V = 6 t = 6000 kg.
- Permissible shear stress τ_perm = 5 kg/cm².
- Applied bending moment M = 24 t·m (given for completeness, but the governing check here is shear).
Concept / Approach:
For preliminary shear safety under working stress methods, the nominal shear stress is estimated as τ_v = V / (b * jd). If τ_v > τ_perm, the section is unsafe in shear, regardless of its adequacy in bending. Appropriate remedies include providing shear reinforcement (stirrups), increasing section size, or reducing shear by layout changes.
Step-by-Step Solution:
Compute τ_v = V / (b * jd).Convert V: 6 t = 6000 kg (force units consistent with kg/cm²).Area resisting shear proxy = b * j*d = 25 cm * 40 cm = 1000 cm².Thus τ_v = 6000 / 1000 = 6 kg/cm².Compare with permissible: 6 kg/cm² > 5 kg/cm² → exceeds allowable shear stress.Verification / Alternative check:
Even if bending is satisfactory (M given as 24 t·m), shear governs because τ_v surpasses τ_perm. Introducing adequate shear reinforcement might help, but as stated, the current check indicates a shear shortfall.
Why Other Options Are Wrong:
- is safe / is over safe: Contradicted by τ_v > τ_perm.
- needs redesigning: Vague; the precise verdict is that it is unsafe in shear (redesign or extra shear steel is needed).
- safe in bending but unsafe in shear: Although true descriptively, the asked judgment focuses on shear adequacy; standard answer is ‘‘is unsafe in shear’’.
Common Pitfalls:
- Mixing units (tonne vs kg) or using total depth instead of effective lever arm for shear check in this classic exam style.
- Assuming bending adequacy implies shear adequacy; both checks are independent.
Final Answer:
is unsafe in shear