Difficulty: Medium
Correct Answer: is unsafe in shear
Explanation:
Introduction / Context:
This problem tests the fundamental shear capacity check for a reinforced concrete (R.C.C.) beam using working-stress style calculations. Even if a beam satisfies bending, it must also be verified that the nominal shear stress does not exceed the permissible (safe) shear stress for the concrete section.
Given Data / Assumptions:
Concept / Approach:
For preliminary shear safety under working stress methods, the nominal shear stress is estimated as τ_v = V / (b * jd). If τ_v > τ_perm, the section is unsafe in shear, regardless of its adequacy in bending. Appropriate remedies include providing shear reinforcement (stirrups), increasing section size, or reducing shear by layout changes.
Step-by-Step Solution:
Compute τ_v = V / (b * jd).Convert V: 6 t = 6000 kg (force units consistent with kg/cm²).Area resisting shear proxy = b * j*d = 25 cm * 40 cm = 1000 cm².Thus τ_v = 6000 / 1000 = 6 kg/cm².Compare with permissible: 6 kg/cm² > 5 kg/cm² → exceeds allowable shear stress.Verification / Alternative check:
Even if bending is satisfactory (M given as 24 t·m), shear governs because τ_v surpasses τ_perm. Introducing adequate shear reinforcement might help, but as stated, the current check indicates a shear shortfall.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
is unsafe in shear
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