Elastic constants relationship: For a material with Poisson’s ratio ν = 0.4, what is the ratio of shear modulus to Young’s modulus (G/E)?
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A5/7
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B7/5
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C5/14
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D14/5
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E2/5
Answer
Correct Answer: 5/14
Explanation
Introduction / Context:In isotropic linear elasticity, the independent constants E (Young’s modulus), G (shear modulus), and ν (Poisson’s ratio) are linked. Converting between them is routine in strength of materials and finite element modeling.
Given Data / Assumptions:
- Isotropic, homogeneous material.
- Poisson’s ratio ν = 0.4.
- Standard elastic relation G = E / [2 * (1 + ν)].
Concept / Approach:Use the canonical relationship connecting E, G, and ν. Substituting ν directly gives the ratio without needing absolute values of E or G.
Step-by-Step Solution:
G = E / [2 * (1 + ν)]With ν = 0.4 ⇒ 1 + ν = 1.4G/E = 1 / [2 * 1.4] = 1 / 2.81 / 2.8 = 0.357142… = 5 / 14Verification / Alternative check:Sanity check: For ν between 0 and 0.5, G/E should lie between 1/3 and 1/2.8; 5/14 ≈ 0.357 fits the expected range.
Why Other Options Are Wrong:
- 5/7, 7/5, 14/5 are greater than 1, impossible for G/E with ν = 0.4.
- 2/5 = 0.4 does not match the exact relation for ν = 0.4.
Common Pitfalls:Forgetting the 2 in the denominator; confusing G/E with E/G; using an incorrect ν value range that yields nonphysical ratios.
Final Answer:5/14