Alphabet series – continue the pattern by constant jumps Sequence: R, U, X, A, D, ?

Difficulty: Easy

Correct Answer: G

Explanation:

Introduction / Context:This is a simple modular alphabet progression. The letters advance by a constant fixed jump, wrapping around after Z to continue from A. Recognizing the jump size reveals the next term immediately.

Given Data / Assumptions:

  • Sequence: R, U, X, A, D, ?
  • Alphabet positions A=1 through Z=26; wrap is applied when the sum exceeds 26.

Concept / Approach:Compute the shift from each letter to the next. If the shift is constant (e.g., +3), maintain it across the wrap point (Z→A) using modular arithmetic.

Step-by-Step Solution:

R(18) → U(21): +3U(21) → X(24): +3X(24) → A(1): +3 with wrap (24 + 3 = 27; 27 − 26 = 1)A(1) → D(4): +3Continue: D(4) → ? = 4 + 3 = 7 → G.

Verification / Alternative check:Apply +3 from the beginning to confirm: R→U→X→A→D→G is perfectly consistent; every step is +3 under wrap.

Why Other Options Are Wrong:

  • F (+2), H (+4), I (+5), J (+6) would each break the uniform +3 increment.

Common Pitfalls:Forgetting to wrap past Z when counting forward; miscounting positions and landing one letter off.

Final Answer:G

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