Dates on which Tuesday fall are 3,10,17, and 24

Hence, the 27th day of the month will be (Tuesday + 3 days=)Friday

Required day of the month = Friday - 4 = Monday

If day before yesterday was Thursday, then today is saturday.

Tomorrow will be sunday

Number of days = (6 + 29 + 31 + 30 + 15) = 111

2008 is a leap year, number of days in february = 29

Given Number :      2 5 6 7 3 9 4 8

Ascending order :  2 3 4 5 6 7 8 9

Specified letters are 6 and 4 respectively.

Hence, required sum = (4 + 6 = 10)

The 2nd, 4th, 7th digits are 3, 1, 6 respectively.

The perfect square of a two-digit odd number, formed using these digits, is 361

and 361 = 19^2

If the year is not a leap year, then last day is same as first day

Number of students behind Manoj in rank = (31 - 7) = 24.

So, Manoj is 25th from the bottom.

Number of students behind Satya in rank = (31 - 11) = 20.

So, Satya is 21st from the bottom.

Total days from 25th June to 15th August = 5 + 31 + 15 = 51 days

51/7  = 7 weeks and 2 days 

August 15 = Wednesday + 2 = Friday

The given numbers are :

382  473  568  728  847  629

When changes are made as given in the question, numbers become as follows :

238  347  856  872  784  962

Again now, find out the difference between the numbers given in options as given below:

(1) 473 - 382  => 347 - 238 = 109

(2) 629 - 728  => 962 - 872 = 90

(3) 629 - 847  => 962 - 784 = 178

(4) 728 - 847  => 872 - 784 = 88

W = 10th from the left

R = 4th from the right = (30 - 4 + 1= ) 27th from left

 No of boys between R and W = (27 - 10) - 1 = 16