The given series follows the rule,
+(11x1), +(11x3), +(11x5), +(11x7), +(11x9),....
So starting from 7, 7 + 11 = 18, 18 + 33 = 51, 51 + 55 = 106, ...
So wrong number is 40 which is to be 51.
the pattern is +6,+9,+12,+15
the missing term is 21+12=33
The first letters of the terms are alternate.
The sequence followed by the numbers is +2, +3, +4,....
The last letter of is three steps ahead of the last letter of the preceding term.
The given series is 118, 166, 190, 202, 208, ?
118
118 + 48 = 166
166 + 24 = 190
190 + 12 = 202
202 + 6 = 208
208 + 3 = 211
In the given series
1st term has odd number starting from 11, So the Series is 11, 13, 15, 17, 19
2nd term has an alphabet follwed by its alpha numeric number in the order +4, +3, +2, +1. So the Series is M13, Q17, T20, V22, W23
Therefore, 15T20 is the answer.
By trial and error method from the given options,
'1' satisfies the above given equation.
The given series is 6, 6, 12, 36, 144, 720, ?
6
6 x 1 = 6
6 x 2 = 12
12 x 3 = 36
36 x 4 = 144
144 x 5 = 720
720 x 6 = 4320
Hence, the next number in the given number series is 4320.
The given number series is 8, 11, 19, 23, 32, ?
It follows a pattern that
8 + 11 = 19
11 + 12 = 23
19 + 13 = 32
23 + 14 = 37
32 + 15 = 47
....
Hence, the next number in the given series = 37.
Each term in the series is obtained by subtracting from the preceding term the number formed by the first three digits of preceding term
So,missing term is 4983-498=4485
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