W ? K ...(i) K > R ....(ii) R = N ...(iii)
Combining these we get W ? K > R = N
Hence N < K and I follows
Again R < W and II follows.
And, W > N III follows.
H ? W ..(i) W < N ...(ii) R = N ...(iii)
Combining these we get H ? W < N = R
Hence R > W and I follows
Again N > W and II follows
And, H < R III follows
Z = M ...(i) M ? F ...(ii) F > D ...(iii)
From (i) and (ii) Z = M ? F or F ? Z ...(iv)
Hence either F = Z (I is true) or F > Z (II follows)
From (iii) and (iv) no relationship can be established between D and Z Hence III does not follow.
D < K ...(i) K = F ...(ii) F ? B ...(iii)
From (i) and (ii) D < K = F or F > D
Hence I is true
From (ii) and (iii) K = F ? B or B ? K. Hence either II
(B < K) or (B = K) is true
Solve by using all option one by one.
Given equation is
24 * 16 * 8 * 32
Taking the sign of option (D),
? 24 + 16 - 8 = 32
Apply the BODMAS Rule in equation.
? 40 - 8 = 32 ? 32 = 32
Hence, correct group of sign is option (b).
Given,
A + B = 2C ----(i)
C + D = 2A----(ii)
Adding (i) and (ii) we get : A + B + C + D = 2C + 2A
=> B + D = A + C
On interchanging - and /, we get the equation as
5 + 3 x 8 / 12 - 4 = 3
or 5 + 3 x (2/3) - 4 = 3
or 3 = 3, which is true.
On interchanging + and - and 4 and 8 in (b),
we get the equation as
8 + 4 - 12 = 0
or 12 - 12 = 0
or 0 = 0, which is true.
By the Given data , We have the expression:
20 + 8 - 8 ÷ 4 × 2 = 20 + 8 - 2 × 2 = 20 + 8 - 4 = 24.
On interchanging + and x and 4 and 5 in (c),
we get the equation as
4 + 5 x 20 = 104 or 104 = 104, which is true.
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