Letter and Symbol Series problems
- 1. If ' + ' mean ' - ' , ' - ' means ' x ', ' x ' means ' ÷ ' and ' ÷ ' means ' + ' , then the value of
16 x 2 ÷ 25 + 7 - 4 is.
Options- A. 104
- B. 5
- C. 22
- D. 4 Discuss
Correct Answer: 5
Explanation:
16 x 2 ÷ 25 + 7 - 4
After replacing the sign according to the given question
16 ÷ 2 + 25 - 7 x 4
Apply the rule BODMAS
B - Brackets first
O - Orders (i.e. Powers and Square Roots, etc.)
DM - Division and Multiplication (left-to-right)
AS - Addition and Subtraction (left-to-right)
= 16 ÷ 2 + 25 - 7 x 4
= 8 + 25 - 28
= 25 - 20
= 5
- 2. If ' - ' stands for ' ÷ ' , ' + ' stands for ' x ' , ' ÷ ' stands for ' - ' and ' x ' stands for ' + ' , find out which one is correct .
Options- A. 49 + 7 - 3 x 5 ÷ 8 = 20
- B. 49 - 7 + 3 ÷ 5 x 8 = 24
- C. 49 x 7 + 3 ÷ 5 - 8 = 16
- D. 49 ÷ 7 x 3 + 5 - 8 = 26 Discuss
Correct Answer: 49 - 7 + 3 ÷ 5 x 8 = 24
Explanation:
Try all option one by one;
From option ( b )
49 - 7 + 3 ÷ 5 x 8 = 24
Change the sign, as per the question,
49 ÷ 7 x 3 - 5 + 8 = 24
Apply the BODMAS rule
B - Brackets first
O - Orders (i.e. Powers and Square Roots, etc.)
DM - Division and Multiplication (left-to-right)
AS - Addition and Subtraction (left-to-right)
Now Applying the BODMAS rule one by one.
49 ÷ 7 x 3 - 5 + 8 = 24
After Division
7 x 3 - 5 + 8 = 24
After Multiplication
21 - 5 + 8 = 24
After Addition
29 - 5 = 24
After subtraction
24 = 24
- 3. Select the correct combination of mathematical signs to replace '*' signs and to balance the following equation.
6 * 4 * 12 * 12
Options- A. ÷, -, =
- B. +. -,÷
- C. =, -, ÷
- D. x, -, = Discuss
Correct Answer: x, -, =
Explanation:
Try all option one by one;
From option (d),
6 * 4 * 12 * 12
Change the sign, as per the question,
6 x 4 - 12 = 12
Apply the BODMAS rule
After Multiplication
24 - 12 = 12
After Substraction
?  12 = 12
- 4. If ' x ' stands for ' + ', ' < ' for ' - ', ' + ', for ' ÷ ', ' > ' for ' x ', ' - ' for ' = ', ' ÷ ' for ' > ' and ' = ' for ' < '. then satae which of the following is true .
Options- A. 3 x 4 > 2 - 9 + 3 < 3
- B. 5 x 3 < 7 ÷ 8 + 4 x 1
- C. 5 > 2 + 2 = 10 < 4 x 8
- D. 3 x 2 < 4 ÷ 16 > 2 + 4 Discuss
Correct Answer: 5 > 2 + 2 = 10 < 4 x 8
Explanation:
Using the proper symbols in ( c ), we get
5 x 2 ÷ 2 < 10 -4 + 8
After Replacing the Sign Apply the BODMAS Rule.
?  5 x 1 < 18 - 4
?  5 < 14
which is true .
- 5. a_c_ba_ca_cb
Options- A. abcc
- B. acba
- C. bcaa
- D. bcba Discuss
Correct Answer: bcba
Explanation:
The sequence is made of repetition of abc in different order, so identify the missing alphabet in abc .
second word is reverse of first word, similar way 4th word is reverse of 3r word.
By option (d),
abc/cba/bca/acb ? bcba
- 6. _cb_ca_bacb_ca_bac_d
Options- A. addddb
- B. addbbb
- C. bddddb
- D. bbbbdd Discuss
Correct Answer: addddb
Explanation:
The sequence is made of repetition of two blocks acbd and cadb alternatively.
acbd/cadb/acbd/cadb/acbd ? addddb
- 7. c_bba_cab_ac_ab_ac
Options- A. bcacb
- B. babcc
- C. abcbc
- D. acbcb Discuss
Correct Answer: acbcb
Explanation:
The sequence is made of repetition of two blocks cab and bac alternatively.
cab/bac/cab/bac/cab/bac ? acbcb
- 8. a_bc_a_bcda_ccd_bcd_
Options- A. abddbd
- B. acbdbb
- C. adbbad
- D. adbcad Discuss
Correct Answer: adbbad
Explanation:
The word aabcd is formed.
2nd word is made by changing to the 2nd position with next alphabet, similarly
3rd word is made by changing to the 3rd position with next alphabet,
4th word is made by changing to the 4th position with next alphabet.
aabcd/abbcd/abccd/abcdd ? adbbad
- 9. a_bc_c_abb_bca_
Options- A. abbba
- B. acccba
- C. cccbc
- D. cbbac Discuss
Correct Answer: acccba
Explanation:
The series is formed of two repeated alphabet at start and end but middle alphabet is not repeated. The word is formed with the help of combination of reordering of abc.
aabcc/ccabb/bbcaa ? accba
- 10. _A 'B_B' AA' _BB' _A
Options- A. A'BAB'
- B. A'B'AB
- C. ABAB
- D. AB'A'B Discuss
Correct Answer: ABAB
Explanation:
The series is made of two consecutive 'A' and three consecutive 'B' in alternate manner.
AA'B/BB'A/A'AB/B'BA ? ABAB
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