Let the first number be K and second number be L
Then, 2K + 3L = 100.....(1)
3K + 2L = 120.......(2)
solving (1)&(2), we get
K = 32 and L = 12
Hence the largest number is 32.
If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29
If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29
If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27
common number is only 23 so it will be answer
Let y be the total number of loaves
a be the remaining loaves after 1st thief
b be the remaining loaves after 2nd thief
and c, d..so on after 3 and 4 th
e = 0 be the remaining loaves after 5th thief
a = y - (y/2 + 1/2)
= y/2 - 1/2
b = a - (a/2 + 1/2)
= a/2 - 1/2
c = b - (b/2 + 1/2)
= b/2 - 1/2
d = c - (c/2 + 1/2)
= c/2 - 1/2
e = d - (d/2 + 1/2)
= d/2 - 1/2
we know that, e = 0,
thus by substitution, we get
d = 1
c = 3
b = 7
a = 15
y = 31
Therefore total number of bread loaves in bakery was 31.
Since floor starts form the 1 therefore 2 will be the 1st floor.
Form 1 to 10 only 4,6,8,9,10 are not prime.
Form 11 to 20 only 14 ,16,18 are not prime also non of their digits are prime.
From 21 to 30 each number has a prime number so it must no be consider.
In between 40 to 49 we have to consider only 40,44,46,48,49.
50 to 59 follow either of the condition so we have too neglect it.
In between 60 to 68 60,64,66,68.
total option = 17.
Here we have 25 divided by 7.
25 will not go directly in 7
Hence, we get the result in decimals.
25/7 = 3.571.
Intial contribution = L/K
After 3 men drop, then contribution =L/K-3
The amount more to pay in contribution =
=
From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ?
Now arranging the given numbers in descending order.
837 746 519 495 328
519 - 746/2 = 519 - 373 = 146.
Assume that the number is taken as XYZ.
Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9
Condition 2 => Y = X + Z
X Y Z
1 2 1
4 6 2
9 12 3 => (wrong because it is 4 digit.)
and 121 is not divisible by 2
The answer is 462.
Sum of Interior angle is 180 .
and it is given that interior angle is 150 more than exterior,
so let exterior angle is x then interior will be x+150
now , interior + exterior =180
x+150+x=180
x=15
now , number of sides of polygon = 360 / exterior angle
n = 360 / 15
n = 24
4, 14, 24, 34, 44, 54, 64, 74, 84, 94 => has 11 number of (4's)
40, 41, 42, 43, 45, 46, 47, 48, 49 => has 9 number of (4's)
So, totally (11 + 9 = 20) number of 4's in 1 to 100.
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