In 40% students failed Hindi then 60% students passed in Hindi.
72% + 44% = 116%
? 16% ? 40
? 100% ? 40 100 16 × = 250
Hence, 16% workers are there who prefer both drinks which are 40 in number.
Required percentage
= 100 ? (40 + 25 + 15)
= 100 ? 80 = 20%
NA
n(A) = 75% of 600 = 450
n(B) = 45% of 600 = 270 and n(A ? B) = 600
? n(A?B) = n (A) + n(B) - n(A?B) = (450 + 270 - 600) = 120
As we know that A ? B consists of the all numbers that are common in both the sets A and B.
The common numbers in the set A and B are 3 , 5 , 7, 11.
Hence the answer will be { 3, 5, 7, 11}.
As we know the formula.
n(A ? B ) = n(A) + n(B) ? n(A ? B )
Given in the question,
n(A) = 40;
n(B) = 26;
n(A ? B ) = 16;
Put these value in formula and solve the equation.
n(A ? B ) = n(A) + n(B) ? n(A ? B )= 40 + 26 ? 16 = 50
A ? B = { a, b, c } ? { c, d, e, f } = { a, b, c, d, e, f }
? (A ? B) ? C = { a, b, c, d, e, f } ? { c, d, e }
= { a, b, c, d, e, f }
= U.
NA
NA
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