Total cost of all varieties of mangoes = 20 x 2 + 40 x 3 + 50 x 5 = 40 + 120 + 250 = Rs. 410

Then, cost of 1 kg mangoes = 410/10 = Rs. 41

To get 20% profit,

The rate at which the mangoes should be sell = 120/100 x 41 = Rs. 49.2

loss % =  c o m m o n g a i n o r l o s s 10 2 %

           = (20/10)x(20/10)% = 4%

Let the cost price of a ball is Rs.x
Given, on selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls
The equation is :
17x - 720 = 5x
Solving the equation
we get x = 60
Therefore, cost price of a ball is Rs. 60.

Let C1 be the cost price of the first article and C2 be the cost price of the second article.
Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.

We know, C1 + C2 = 600.
The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.

The total selling price of the first and second article = 1.22C1 + 0.92C2.

As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.

Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
1.22C1 + 0.92(600 - C1) = 600
or 1.22C1 - 0.92C1 = 600 - 0.92*600
or 0.3C1 = 0.08*600 = 48
or C1 = 48/(0.3) = 160.
If C1 = 160, then C2 = 600 - 160 = 440.
The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.

Let the cost price of the fruits be 'C.P'

From the given data, after analysis it can be solved as

(121% of C.P) - (125% of 91% of C.P) = 29

$$\begin{gathered} 121 100 C . P - 125 100 x 91 100 x C . P = 29 \\ 121 100 - 125 x 91 100 x 100 C . P = 29 \\ ( 12100 - 125 x 91 ) C . P = 290000 \\ ( 12100 - 11375 ) C . P = 290000 \\ 725 C . P = 290000 \\ C . P = 400 \end{gathered}$$

Hence, the cost price of the fruits = Rs. 400.

Cost price = Rs. 30

Selling price = Rs. 50

Gain = Rs. 20

Profit % = Gain/cost price x 100 = 20/50 x 100 = 40%

Let the profit be Rs. p

Then Cost price of the bag = 340p/100 = 3.4p

According to question,

3.4p + p = 1540

4.4p = 1540

p = 1540/4.4

p = 350

The profit p = Rs, 350

Hence, The cost price of the bag = 3.4p = 3.4 x 350 = Rs. 1190.

Let C.P =Rs. x

Then as given, (753 - x ) = (x - 455)

=>2x = 1208 => x = 604

 There fore S.P= 150% of 604 => Rs.  150 100 × 604= Rs.906

Let?s assume John bought the laptop for Rs. 100
He then sells it to Mark at a loss of 20% => Rs. 80,
Who consequently sells it to Kevin at a profit of 25% =>  Rs. 100
Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10
Therefore, for Rs. 100 there is a loss of Rs. 10,
Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.

Let the Cost of Production of the article = 100

Then, Labour Cost = 20

Raw Material = 10

Other Expenditure = 100 - 10 ? 20 = 70

Selling Price of the article  = 120

After increasing Labour and Raw material cost by 40% & 20% respectively,

New Labour cost = 28

New Raw material cost = 12

New Cost of Production = 70 + 28 + 12 = 110

Then, New SP = 110% of 120 = 120 x 110/100 = 132

=> New Gain = 132 - 110 = 22

=> New Profit % = 22 x 100/110 = 20%