Problems on Ages
- 1. Two trains of length 50 m and 65 m are moving in the same direction at 18 m/s and 17 m/s, respectively. Find the time taken by the faster train to cross the slower train.?
Options- A. 100 s
- B. 114 s
- C. 95 s
- D. 115 s Discuss
Correct Answer: 115 s
Explanation:
According to the formula.
Required time = (x + y)/(u - v)
Here , x = 50 m , y = 65 m , u = 18 m/s and v = 17 m/s
? Required time = (50 + 65)/(18 - 17) = 115/ 1 = 115 s
- 2. Raju decided to marry 3 yr after he gets a job. He was 17 yr old when he passed class 12th. After passing class 12th, he had completed his graduation course in 3 yr and PG course in 2 yr. He got the job exactly 1 yr after completing his PG course. At what age will he get married?
Options- A. 27 yr
- B. 26 yr
- C. 28 yr
- D. 23 yr Discuss
Correct Answer: 26 yr
Explanation:
? Age of Raju when he got the job = 17 + 3 + 2 + 1 = 23 yr
? Age of Raju at the time of marriage = 23 + 3 = 26 yr
- 3. At present Meena is eight times her daughter's age. 8 yr from now, the ratio of the ages of Meena and her daughter will be 10 : 3, respectively. What is Meena's present age?
Options- A. 32 yr
- B. 40 yr
- C. 36 yr
- D. Cannot be determined Discuss
Correct Answer: 32 yr
Explanation:
Let age of daughter = N yr
? Age of Meena = 8N yr
Accounting to the question, (8N + 8)/(N + 8) = 10/3
? 24N + 24 = 10N + 80
? 14N = 56
? N = 4
Hence, Meena's present age = 4 x 8 = 32 yr
- 4. Before 7 yr, the ratio of ages of A and B was 3 : 4 after 9 yr, ratio of their ages will be 7 : 8. The present age of B will be
Options- A. 16 yr
- B. 19 yr
- C. 28 yr
- D. 23 yr Discuss
Correct Answer: 23 yr
Explanation:
Let the ages of A and B before 7 yr were 3k yr and 4k yr, respectively.
? Present age of A = 3k + 7
and present age of B = 4k + 7
Now, according to the question,
? (3k + 7 + 9) / (4k + 7 + 9) = 7/8
? 24k + 128 = 28k + 112
? 4k = 16
? k = 4
Hence, present age of B = 4 x 4 + 7
= 16 + 7 = 23 yr
- 5. The ratio between the present ages of Tarun and Varun is 3 : 7, respectively. After 4 yr, Varun's age will be 39 yr. What was Tarun's age 4 yr ago?
Options- A. 12 yr
- B. 13 yr
- C. 19 yr
- D. 18 yr Discuss
Correct Answer: 18 yr
Explanation:
Let Tarun and Varun's ages are 3k yr and 7k yr, respectively.
? 7k + 4 = 39
? k = 5
Hence, Tarun's age 4 yr ago = 3 x 5 - 4 = 11 yr
- 6. The ratio of the ages of Ram and Rahim 10 yr ago was 1 : 3 . The ratio of their ages five years hence will be 2 : 3. Then, the ratio of their present ages is?
Options- A. 1 : 2
- B. 3 : 5
- C. 3 : 4
- D. 2 : 5 Discuss
Correct Answer: 3 : 5
Explanation:
Let 10 yr ago, ages of Ram and Rahim were k yr and 3k yr, respectively.
Then, present age of Ram = (k + 10)
and present age of Rahim = (3k + 10)
According to the question, (k + 10 + 5) / (3k + 10 + 5) = 2/3
? 3k + 45 = 6k + 30
? 3k = 15
? k = 5
Hence, required ratio = (5 + 10) / (3 x 5 + 10)
= 15/25
= 3 : 5
- 7. The ages of Harsh and Sumit are 40 yr and 60 yr, respectively. How many year before the ratio of their ages was 3 : 5?
Options- A. 15 yr
- B. 20 yr
- C. 37 yr
- D. 10 yr Discuss
Correct Answer: 10 yr
Explanation:
Let k yr before, the ratio of their ages was 3 : 5.
According to the question
(40 - k)/(60 - k) = 3/5
? 200 - 5k = 180 - 3k
? 2k = 20
? k = 10
- 8. The present age of Ravi's father is four times Ravi's present age.Five years back, Ravi's father was seven times as old as Ravi was at that time. What is the present age of Ravi's father?
Options- A. 84 yr
- B. 70 yr
- C. 40 yr
- D. 35 yr Discuss
Correct Answer: 40 yr
Explanation:
Let present age of Ravi be k.
Then, Present age of Ravi's father = 4k.
Now, 5 yr ago,
Ravi's father's age = 7 x Ravi's age
? 4k - 5 = 7(k - 5)
? 4k - 5 = 7k - 35
? 3k = 30
? k = 10
? Ravi's present age = k = 10 yr
? Ravi's father's present age = 4k
= 4 x 10 = 40 yr
- 9. 3 yr before, the average age of a family of 5 members was 17 yr. Due to birth of a new child, the average age is same today. The present age of child is?
Options- A. 1 yr
- B. 3 yr
- C. 21/2 yr
- D. 2 yr Discuss
Correct Answer: 2 yr
Explanation:
3 yr before, total age of 5 members = 17 x 5 = 85 yr
? The present age of all members of family = 85 + 3 x 5 = 100 yr
Let the age of child be N yr.
? Present average age of family including the child
= (100 + N)/6
? 17 = (100 + N)/6
? N = 102 - 100 = 2 yr
- 10. The ratio of present ages of two brothers is 1 : 2 and 5 years ago the ratio was 1: 3. What will be the ratio of their ages after 5 years?
Options- A. 1 : 4
- B. 2 : 3
- C. 3 : 5
- D. 5 : 6 Discuss
Correct Answer: 3 : 5
Explanation:
Let us assume their present ages be x and 2x years; then
5 years ago ages of the brothers was x - 5 and 2x - 5 years.
According to question, 5 years ago the ratio was 1: 3
( x - 5)/(2x - 5) = 1/3
? 3x-15 = 2x -5
? x = 10
Hence, their present ages 10 years and 20 years.
Ages after 5 years will be 10 +5 and 20 + 5 Years
Required ratio = 10+5/20 + 5 = 15/25 = 3/5 = 3 : 5
More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.