Problems on Ages
- 1. A father's age is three times the sum of the ages of his two children but 20 years hence his age will be equal to the sum of their ages. Then the father's age is?
Options- A. 30 years
- B. 40 years
- C. 35 years
- D. 45 years Discuss
Correct Answer: 30 years
Explanation:
Let the present age of father be x years and the sum of present ages of 2 sons be y years.
? x = 3y ...(i)
? (x + 20) = (y + 20 + 20) ...(ii) [20 will be added twice as for 2 children]
Solving (i) and (ii), we get
x = 30 years
- 2. If C's age is twice the average age of A, B and C, A's age is one half the average of A, B and C. If B is 5 years old, the average age of A, B and C is?
Options- A. 10 years
- B. 15 years
- C. 12 years
- D. 9 years Discuss
Correct Answer: 10 years
Explanation:
Let the average age of A, B and C be N years.
? Total age of A, B and C = 3 x N = 3N years
Now, according to the question,
? 3N - (2N + N/2) = 5
? N = 10 years.
- 3. Two years ago, a mother was four times as old as her daughter. 8 years later, mother's age will exceed her daughter's age by 12 years. The ratio of the present ages of mother and daughter is?
Options- A. 3 : 1
- B. 4 : 1
- C. 3 : 2
- D. 5 : 1 Discuss
Correct Answer: 3 : 1
Explanation:
Let the mother's age 2 years ago be 4x and daughter's age 2 years ago be be x.
? (4x + 8) - (x + 8) = 12
? 3x = 12
? x = 4
? Mother's present age = 4x + 2 = 18 years
and daughter's present age = x + 2 = 6 years
? Required ratio = 3 : 1
- 4. Five years ago, the total of the ages of father and son was 60 years. The ratio of their present ages is 4 : 1. Then the present age of the father is?
Options- A. 48 years
- B. 51 years
- C. 56 years
- D. 61 years Discuss
Correct Answer: 56 years
Explanation:
Let the present age of the son be x and that of the father be 4x years.
? (x - 5) + (4x - 5) = 60
? 5x = 70
? x = 14 years
? Father's present age = 4x = 56 years
- 5. A is as much younger than B as he is older then C. If the sum of B's and C's age is 40 years. Find the age of A.?
Options- A. 20 years
- B. 25 years
- C. 30 years
- D. 27 years Discuss
Correct Answer: 20 years
Explanation:
Age of C < Age of A < Age of B
From question,
A = C + x ....(i)
B = A + x ....(ii)
From equation (i) and (ii)
A - B = C - A
? 2A = B + C
? A = (B + C) / 2
Given that sum of the ages of B and C is 40 years.
So, A = (B + C) / 2 = 40/2 = 20 Years
- 6. A says to B "I am twice as old as you were when I was as old as you are." The sum of their ages is 63 years. Find the difference of their ages?
Options- A. 27 years
- B. 12 years
- C. 9 years
- D. 6 years Discuss
Correct Answer: 9 years
Explanation:
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
- 7. 15 years later, A will be twice as old as B but five years ago A was 4 times as old as B. Find the difference of their present ages?
Options- A. 15 years
- B. 45 years
- C. 30 years
- D. 25 years Discuss
Correct Answer: 30 years
Explanation:
Let A's age = x years and B's age = y years
As per the first condition,
? (x + 15) = 2(y + 15)
? x - 2 y = 15 ....(i)
As the per second condition,
? (x - 5) = 4(y - 5)
? x - 4 y = -15 ....(ii)
Solving (i) and (ii) one get's, x = 45, y = 15
? A's age = 45 years
B's age = 15 years
? Difference of their ages = 45 - 15 = 30 years
- 8. The ratio of the present ages of a son and his father is 1 : 5 and that of his mother and father is 4 : 5. After 2 years the ratio of the age of the son to that of his mother becomes 3 : 10. What is the present age of the father?
Options- A. 30 years
- B. 28 years
- C. 27 years
- D. None of these Discuss
Correct Answer: None of these
Explanation:
? S / F = 1 / 5
? F = 5 S, .....(i)
? M / F = 4 / 5
? M = 4 / 5 F ....(ii)
? (S + 2) / (M + 2) = 3 / 10
? 10S + 20 = 3M + 6 ....(iii)
From (i), (ii) and (iii)
? (12 - 10)S = 20 - 6
? 2S = 14
? S = 7 years
? F = 5S = 5 x 7 = 35 years.
- 9. The product of the ages of Harish and Seema is 240 . If twice the age of seema is more then Harish's age by 4 years. What is seema's age in years?
Options- A. 12 years
- B. 20 years
- C. 10 years
- D. 14 years Discuss
Correct Answer: 12 years
Explanation:
Let the ages of Harish and Seema be x and y respectively.
According to the question,
xy = 240 ....(i)
2y - x = 4 ....(ii)
Solving equations (i) and (ii), we get
y = 12 years
- 10. If the age of P and R are added to twice the age of Q the total becomes 59. If the ages of Q and R are added to thrice the age of P the total becomes 68. And if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. what is the age of P T?
Options- A. 15 years
- B. 19 years
- C. 17 years
- D. 12 years Discuss
Correct Answer: 12 years
Explanation:
P + R + 2 Q = 59, ....(i)
Q + R + 3 P = 68 .....(ii)
and P + 3 (Q + R) = 108 ......(iii)
Solving the above three equations, we get
? P + 3 (68 - 3P) = 108
? P + 204 - 9P = 108
? P = 12 years.
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