Let the number be x, y, z
Then,
x + y = 45,
y + z = 55,
z + 3x = 30
Now, y = (45 - x) and
z = 55 - y
? z = 55 - (45 - x ) = 10 + x
? 10 + x + 3x = 90
? x = 20
So, third number = z
= 10 + x = 30
The number is of the form (5x + 3 ) where x is an integer
? [(5x + 3)2] / 5 = ( 25x2 + 30x + 9) / 5
= 25x2/ 5 + 30x/5 + (5 +4)/5
? The remainder is 4.
According to the question
Divisor = 2/3 x dividend
and Divisor = 2 x remainder
or 2/3 x dividend = 2 x 5
? Dividend = 2 x 5 x 3 / 2 = 15
Number of one digit pages from
1 to 9 = 9
Number of two digit pages from
10 to 99 = 90
Number of three digit pages from
100 to 200 = 101
? Total number of required figures
= 9 x 1 + 90 x 2 + 101 x 3 = 492
Let 1/2 of the no. = 10x + y
and the no. = 10v + w
From the given conditions,
w= x and v = y-1
Thus the no. = 10 (y-1) + x
? 2(10x + y ) = 10 (y-1) + x
? 8y - 19x = 10 ...(i)
v + w = 7
? y-1 + x = 7
? x + y = 8
Solving equations (i) and (ii) , we get
x = 2 and y = 6
? From equations (A)
Number = 10 (y - 1) + x = 52.
Let the two-digit number be 10x + y
10x + y = 7(x + y)
? x = 2y ...(i)
10(x +2 ) + (y + 2) = 6(x + y + 4) + 4
or 10x + y + 22 = 6x + 6y + 28
? 4x - 5y = 6 ...(ii)
Solving equations (i) and (ii)
We get x = 4 and y = 2
Let the number be x.
? (x - 4)/6 = 9
? x = 58
Again (x - 3)/5 = (58 - 3)/5 = 11
xy = 96050 ...(i)
and xz = 95625 ...(ii)
and y - z = 1 ... (iii)
Dividing (i) by (ii) we get
y/z = 96050 / 95625
= 3842 / 3825
= 226 / 225 ... (iv)
Combining (iii) and (iv) we get z = 225.
Let the two numbers be 3N and 2N
According to the question.
10 + (3N +2N ) + (3N x 2N) = 162
? 6N2 + 5N - 246 = 0
? 6N2 + 41N - 36N - 246 = 0
? N(6N + 41 ) - 6(6N + 41) = 0
? (6N + 41 ) (N - 6) = 0
? N = 6 or -41/6 (But -ve value cannot be accepted )
? Smaller number = 2N = 2 x 6 = 12 .
Let the original number be 10p + q.
So from question,
q = 2p + 1 ...(i)
and (10q + p) - (10p + q ) = (10p + q) - 1
? 9q - 9p = 10p + q -1
? 19p - 8q = 1...(ii)
Putting the value of (i) in equation (ii) we get
19p - 8(2p + 1) = 1
? 19p - 16p - 8 = 1
? 3p = 9
? p = 3
So, q = 2 x 3 + 1 = 7
? Original number = 10 x 3 + 7 = 37
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