Given, P = 10 crore
and population after 3 yr = 13.31 crore
According to the formula,
Population after n yr = P (1 + R/100 )n
? 13.31 = 10 (1 + R/100 )3
? 1331/1000 = (1 + R/100 )3
? (11/10)3 = (1 + R/100 )3
? 1 + R/100 = 11/10
? R/100 = 11/10 - 1 = 1/10
? R = 10%
Given, R = 8%, D = ? 32 and P = ?
By formula, D = P(R/100)2
? 32 = P(8/100)2
? P = 32 x [(100 x 100)/(8 x 8)]
= ? 5000
Let the amount be ? P
R = 5%, n = 2 yr and CI ? 410
By formula, CI = P [ (1 + R/100)n - 1 ]
? 410 = P [ (1 + 5/100)2 - 1]
? 410 = P [ (1 + 1/20)2 - 1]
? 410 = P [ (21/20)2 - 1]
? 410 = P [ 441/400 - 1 ]
? 410 = P [(441 - 400) /400] = P x 41/400
? P = (410 x 400)/41
? P = ? 4000
Let sum = P
and given that n = 3 yr
According to the question,
Amount = 27 P
According to the formula,
Amount = P (1 + R/100)n
? 27 P = P (1 + R/100)3
? 27 = (1 + R/100)3
? (1 + R/100)3 = (3)3
? 1 + R/100 = 3
? R/100 = 3 - 1 = 2
? R = 200%
? 30000 x (1 +7/100)t = 30000 + 4347
? (107/100)t = 34347/30000
?11449/10000 = (107/100)2
? Time = 2 years
C.I. when reckoned half yearly
= Rs.[800 x (1 + 10/100)2 - 800]
= Rs. 168
C.I.when reckoned quarterly
= Rs.800[(1 + 5/100)4 - 1]
= 800[(194481 - 160000)/160000]
= 34481/200
= Rs.172.40
? Required difference =Rs.(172.40 - 168)
= Rs.4.40
C.I. = Rs[20480 x(1 +25/4 x 100)2 (1 + 1/5 x 25/4 x 100) - 20480 ]
= Rs.[(20480 x 17/16 x 17/16 x 81/80) - 20480]
= 20480[23409 - 20480/20480]
= Rs .2929
? S.I. for 1 year =Rs. 1440
? S.I. on Rs.1440 for 1 year = Rs.160
Hence, ? Rate per cent = (100 x 160) / (1440 x 1) %
= 100/9%
= 111/9%
S.I. for first year = Rs. 400
S.I. on Rs .400 for 1 year =Rs. 32
? Rate = (interest x 100)/(principle x time) = (100 x 32)/(400 x 1) = 8%
Hence, the difference for 3rd year is S.I.on Rs. 832
= Rs.(832 x 8/100)
= Rs. 66.56
? Total difference = Rs.(32 + 66.56)
= Rs. 98.56
Balance = Rs.[{4000 x (1 x 15/2 x 100)3} - {1500 x (1 + 15/2 x 100)2 + 1500 x (1 + 15/2 x 100) + 1500}]
= Rs. 123.25
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